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Ch. 4 - Applications of the Derivative
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.R.65

60–81. Limits Evaluate the following limits. Use l’Hôpital’s Rule when needed. 


lim_Θ→0 2Θ cot 3Θ

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Identify the form of the limit as \( \Theta \to 0 \). The expression \( 2\Theta \cot 3\Theta \) can be rewritten as \( \frac{2\Theta}{\tan 3\Theta} \). As \( \Theta \to 0 \), both the numerator \( 2\Theta \) and the denominator \( \tan 3\Theta \) approach 0, resulting in an indeterminate form \( \frac{0}{0} \).
Since the limit is in the indeterminate form \( \frac{0}{0} \), apply l'Hôpital's Rule, which states that \( \lim_{x \to a} \frac{f(x)}{g(x)} = \lim_{x \to a} \frac{f'(x)}{g'(x)} \) if the limit is indeterminate. Differentiate the numerator and the denominator separately.
Differentiate the numerator \( 2\Theta \) with respect to \( \Theta \). The derivative is \( 2 \).
Differentiate the denominator \( \tan 3\Theta \) with respect to \( \Theta \). Using the chain rule, the derivative is \( 3 \sec^2 3\Theta \).
Substitute the derivatives back into the limit: \( \lim_{\Theta \to 0} \frac{2}{3 \sec^2 3\Theta} \). Simplify the expression and evaluate the limit as \( \Theta \to 0 \).

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