Ch. 6 - Applications of Integration

Briggs - Calculus: Early Transcendentals 3rd Edition

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Briggs 3rd Edition

Ch. 6 - Applications of Integration

Problema 6.1.10d

Capitolo 6, Problema 6.1.10d

9–10. Velocity graphs The figures show velocity functions for motion along a line. Assume the motion begins with an initial position of s(0)=0. Determine the following.

d. A piecewise function for s(t)

Guida verificata passo dopo passo

Step 1: Understand that the velocity function \(v(t)\) is the derivative of the position function \(s(t)\), so \(s(t)\) can be found by integrating \(v(t)\) with respect to \(t\).

Step 2: Identify the piecewise definition of \(v(t)\) from the graph. For \(0 \leq t \leq 3\), \(v(t) = 3\). For \(3 < t \leq 5\), \(v(t)\) decreases linearly from 3 to 0, so find the equation of the line connecting points \((3,3)\) and \((5,0)\).

Step 3: Write the velocity function as a piecewise function: \(v(t) = \begin{cases} 3 & 0 \leq t \leq 3 \\ m t + b & 3 < t \leq 5 \end{cases}\) where \(m\) and \(b\) are the slope and intercept of the line segment from \(t=3\) to \(t=5\).

Step 4: Integrate each piece of \(v(t)\) to find \(s(t)\). For \(0 \leq t \leq 3\), integrate the constant velocity 3 to get \(s(t) = 3t + C_1\). Use the initial condition \(s(0) = 0\) to find \(C_1\).

Step 5: For \(3 < t \leq 5\), integrate the linear velocity function \(m t + b\) to get \(s(t) = \frac{m}{2} t^2 + b t + C_2\). Use continuity of \(s(t)\) at \(t=3\) to solve for \(C_2\).

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Relationship Between Velocity and Position

Velocity is the derivative of position with respect to time, meaning that the position function s(t) can be found by integrating the velocity function v(t). Given an initial position s(0), integrating v(t) over time gives the displacement from the initial position.

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06:29

Derivatives Applied To Velocity

Piecewise Functions

A piecewise function is defined by different expressions over different intervals of the domain. In this problem, the velocity graph changes behavior at t=3 and t=5, so the position function s(t) must be expressed as a piecewise integral of v(t) over these intervals.

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05:36

Piecewise Functions

Definite Integration and Area Under the Curve

The position change over an interval is the definite integral of velocity over that interval, which corresponds to the area under the velocity curve. Calculating these areas for each piece of the velocity graph allows us to construct the position function s(t).

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05:43

Definition of the Definite Integral

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