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Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoBriggs 3rd EditionCh. 7 - Logarithmic, Exponential Functions, and Hyperbolic FunctionsProblema 7.R.33b
Capitolo 7, Problema 7.R.33b

Derivatives of hyperbolic functions Compute the following derivatives.
b. d/dx (x sech x)

Guida verificata passo dopo passo
1
Identify the function to differentiate: \(f(x) = x \cdot \text{sech}(x)\), which is a product of two functions, \(x\) and \(\text{sech}(x)\).
Recall the product rule for derivatives: if \(f(x) = u(x) v(x)\), then \(f'(x) = u'(x) v(x) + u(x) v'(x)\).
Compute the derivative of the first function: \(u(x) = x\), so \(u'(x) = 1\).
Compute the derivative of the second function: \(v(x) = \text{sech}(x)\). Use the fact that \(\frac{d}{dx} \text{sech}(x) = -\text{sech}(x) \tanh(x)\).
Apply the product rule: \(f'(x) = 1 \cdot \text{sech}(x) + x \cdot (-\text{sech}(x) \tanh(x))\), then simplify the expression as needed.

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Derivative of a Product

When differentiating a product of two functions, use the product rule: (fg)' = f'g + fg'. This rule allows you to find the derivative of expressions like x·sech(x) by differentiating each part separately and combining the results.
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The Product Rule

Derivative of the Hyperbolic Secant Function (sech x)

The hyperbolic secant function, sech(x), is defined as 1/cosh(x). Its derivative is -sech(x)·tanh(x), which is essential to apply when differentiating expressions involving sech(x).
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Derivative of the Natural Exponential Function (e^x)

Hyperbolic Functions and Their Properties

Hyperbolic functions like sinh, cosh, and sech have properties similar to trigonometric functions but relate to exponential functions. Understanding their definitions and relationships helps in differentiating and simplifying expressions involving them.
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Percorso guidato
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Properties of Functions
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