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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.R.15

2–74. Integration techniques Use the methods introduced in Sections 8.1 through 8.5 to evaluate the following integrals.
15. ∫ (from 1 to 2) (3x⁵ + 48x³ + 3x² + 16)/(x³ + 16x) dx

Guida verificata passo dopo passo
1
Step 1: Simplify the integrand by factoring the denominator. The denominator is \(x^3 + 16x\), which can be factored as \(x(x^2 + 16)\). Rewrite the integrand as \((3x^5 + 48x^3 + 3x^2 + 16) / (x(x^2 + 16))\).
Step 2: Break the integrand into partial fractions. Express the numerator \(3x^5 + 48x^3 + 3x^2 + 16\) as a sum of terms that can be divided by \(x(x^2 + 16)\). This involves finding constants \(A, B, C\) such that \(\frac{A}{x} + \frac{Bx + C}{x^2 + 16}\) equals the original fraction.
Step 3: Solve for the constants \(A, B, C\) by equating coefficients after multiplying through by the denominator \(x(x^2 + 16)\). This step involves algebraic manipulation to match terms on both sides of the equation.
Step 4: Integrate each term separately. The term \(\frac{A}{x}\) integrates to \(A \ln|x|\), and the term \(\frac{Bx + C}{x^2 + 16}\) can be split further into simpler integrals using substitution techniques or standard integral formulas for rational functions.
Step 5: Evaluate the definite integral by substituting the limits of integration (from \(x = 1\) to \(x = 2\)) into the antiderivative obtained in Step 4. Simplify the result to complete the solution.

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