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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.5.12

5–16. Set up the appropriate form of the partial fraction decomposition for the following expressions. Do not find the values of the unknown constants.
12. (2x² + 3)/((x² - 8x + 16)(x² + 3x + 4))

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1
Identify the factors in the denominator: \(x^{2} - 8x + 16\) and \(x^{2} + 3x + 4\). Notice that \(x^{2} - 8x + 16\) is a perfect square trinomial and can be factored as \((x - 4)^{2}\). The other quadratic \(x^{2} + 3x + 4\) does not factor nicely over the reals, so it remains as is.
Since \((x - 4)^{2}\) is a repeated linear factor, set up terms for both the first power and the second power of \((x - 4)\) in the decomposition. For each linear factor, the numerator is a constant: \(\frac{A}{x - 4} + \frac{B}{(x - 4)^{2}}\).
For the irreducible quadratic factor \(x^{2} + 3x + 4\), the numerator must be a linear expression of the form $Cx + D$ because the degree of the numerator is one less than the degree of the denominator factor.
Combine all parts to write the partial fraction decomposition setup as: \(\frac{A}{x - 4} + \frac{B}{(x - 4)^{2}} + \frac{Cx + D}{x^{2} + 3x + 4}\).
This setup is the appropriate form for the partial fraction decomposition of the given expression. The next step (not required here) would be to multiply both sides by the denominator and solve for the constants \(A\), \(B\), \(C\), and \(D\).

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Partial Fraction Decomposition

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Factoring quadratic expressions involves rewriting a quadratic polynomial as a product of simpler polynomials. Recognizing perfect square trinomials or irreducible quadratics is essential to determine the correct form of partial fractions, especially when denominators contain quadratic factors.
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