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Ch. 9 - Differential Equations
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 9, Problema 9.5.1

Explain how the growth rate function determines the solution of a population model.

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Understand that in population models, the growth rate function describes how the population changes over time, often expressed as a function of the current population size, say \(r(P)\), where \(P\) is the population at time \(t\).
Recognize that the population model is typically formulated as a differential equation of the form \(\frac{dP}{dt} = r(P) \cdot P\), where \(\frac{dP}{dt}\) represents the rate of change of the population with respect to time.
Analyze how the form of the growth rate function \(r(P)\) influences the behavior of the solution: for example, if \(r(P)\) is constant and positive, the population grows exponentially; if \(r(P)\) decreases as \(P\) increases, it may model limited resources leading to logistic growth.
Solve the differential equation by separating variables or using an integrating factor, depending on the form of \(r(P)\), to find the explicit solution \(P(t)\) that describes the population at any time \(t\).
Interpret the solution \(P(t)\) in terms of the growth rate function to understand long-term behavior such as equilibrium points, carrying capacity, or unbounded growth, which are all determined by the characteristics of \(r(P)\).

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Growth Rate Function

The growth rate function describes how the population changes over time, often expressed as a rate of change dependent on the current population size. It can be constant or vary with population, influencing whether the population grows, declines, or stabilizes.
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Intro To Related Rates

Differential Equations in Population Models

Population models are typically formulated as differential equations where the growth rate function defines the derivative of the population with respect to time. Solving these equations provides the population size as a function of time, revealing the dynamics of growth.
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Classifying Differential Equations

Equilibrium Solutions and Stability

Equilibrium solutions occur when the growth rate is zero, indicating a stable or unstable population size. Analyzing these points helps predict long-term behavior of the population, such as whether it will settle at a steady state or experience unbounded growth or decline.
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Solutions to Basic Differential Equations
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Domanda del libro di testo

17–32. Solving initial value problems Determine whether the following equations are separable. If so, solve the initial value problem.

y'(t) = y³sin t, y(0) = 1

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7–16. Verifying general solutions Verify that the given function is a solution of the differential equation that follows it. Assume C, C1, C2 and C3 are arbitrary constants.

u(t) = C₁eᵗ + C₂teᵗ; u''(t) - 2u'(t) + u(t) = 0

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Domanda del libro di testo

The general solution of a first-order linear differential equation is y(t) = Ce⁻¹⁰ᵗ − 13. What solution satisfies the initial condition y(0) = 4?

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Domanda del libro di testo

9–14. Growth rate functions Make a sketch of the population function P (as a function of time) that results from the following growth rate functions. Assume the population at time t = 0 begins at some positive value.


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Domanda del libro di testo

9–14. Growth rate functions Make a sketch of the population function P (as a function of time) that results from the following growth rate functions. Assume the population at time t = 0 begins at some positive value.


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Domanda del libro di testo

45–48. General first-order linear equations Consider the general first-order linear equation y'(t)+a(t)y(t)=f(t). This equation can be solved, in principle, by defining the integrating factor p(t)=exp(∫a(t)dt). Here is how the integrating factor works. Multiply both sides of the equation by p (which is always positive) and show that the left side becomes an exact derivative. Therefore, the equation becomes


p(t)(y′(t) + a(t)y(t)) = d/dt(p(t)y(t)) = p(t)f(t).


Now integrate both sides of the equation with respect to t to obtain the solution. Use this method to solve the following initial value problems. Begin by computing the required integrating factor.


y′(t) + (2t)/(t² + 1)y(t) = 1 + 3t², y(1) = 4

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