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Ch. 1 - Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 65

In Exercises 65–68, ABC is a right triangle with the right angle at C. The sides opposite angles A, B, and C are a, b, and c, respectively.


a. Find a and b if c = 2, B = π/3.
b. Find a and c if b = 2, B = π/3.

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1
To solve part (a), we start by using the given information: c = 2 and angle B = π/3. Since ABC is a right triangle, we can use trigonometric ratios. The side opposite angle B is b, and the hypotenuse is c.
Use the sine function for angle B: sin(B) = opposite/hypotenuse = b/c. Substitute the known values: sin(π/3) = b/2. Solve for b using the fact that sin(π/3) = √3/2.
Next, use the cosine function for angle B: cos(B) = adjacent/hypotenuse = a/c. Substitute the known values: cos(π/3) = a/2. Solve for a using the fact that cos(π/3) = 1/2.
For part (b), we are given b = 2 and angle B = π/3. We need to find a and c. Use the tangent function for angle B: tan(B) = opposite/adjacent = b/a. Substitute the known values: tan(π/3) = 2/a. Solve for a using the fact that tan(π/3) = √3.
Finally, use the Pythagorean theorem to find c: a² + b² = c². Substitute the known values for a and b to solve for c.

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Pythagorean Theorem

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