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Ch. 2 - Limits and Continuity
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 2.4.35

Using limθ→0 sin θ / θ = 1


Find the limits in Exercises 23–46.


limt→0 sin(1 − cos t) / (1 − cos t)

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Recognize that the limit involves the expression sin(1 - cos t) / (1 - cos t) as t approaches 0. This is a form that can be related to the standard limit lim(θ→0) sin(θ)/θ = 1.
To use the standard limit, we need to manipulate the expression to match the form sin(θ)/θ. Notice that both the numerator and the denominator have the same expression (1 - cos t).
Apply the standard limit by setting θ = 1 - cos t. As t approaches 0, cos t approaches 1, making θ approach 0.
Rewrite the limit in terms of θ: lim(t→0) sin(1 - cos t) / (1 - cos t) becomes lim(θ→0) sin(θ)/θ.
Since lim(θ→0) sin(θ)/θ = 1, conclude that the original limit also equals 1.

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