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Ch. 2 - Limits and Continuity
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 2.4.34

Using limθ→0 sin θ / θ = 1


Find the limits in Exercises 23–46.


llimx→0 (x −x cos x) / sin² 3x

Guida verificata passo dopo passo
1
Recognize that the problem involves a limit as x approaches 0, and the expression includes trigonometric functions. The key identity given is lim(θ→0) (sin θ / θ) = 1, which will be useful in simplifying the expression.
Rewrite the expression (x - x cos x) / sin²(3x) by factoring out x from the numerator: x(1 - cos x) / sin²(3x). This helps in isolating the trigonometric part of the expression.
Apply the trigonometric identity 1 - cos x ≈ (x²/2) as x approaches 0. This approximation is useful for simplifying the numerator further.
Substitute the approximation into the expression: x(x²/2) / sin²(3x). This simplifies to x³/2sin²(3x).
Use the identity lim(θ→0) (sin θ / θ) = 1 to simplify sin²(3x). Recognize that sin²(3x) can be rewritten as (sin(3x)/3x)² * (3x)². As x approaches 0, (sin(3x)/3x) approaches 1, allowing further simplification of the limit.

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