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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.7.109c

Applications


Suppose that f(x) = d/dx (1 − √x) and g(x) = d/dx (x + 2).


Find:


∫[−f(x)] dx

Guida verificata passo dopo passo
1
First, identify the functions f(x) and g(x) as derivatives given in the problem: \( f(x) = \frac{d}{dx} (1 - \sqrt{x}) \) and \( g(x) = \frac{d}{dx} (x + 2) \).
Calculate \( f(x) \) by differentiating the function inside: \( 1 - \sqrt{x} = 1 - x^{1/2} \). Use the power rule for differentiation: \( \frac{d}{dx} x^{n} = n x^{n-1} \).
Express \( f(x) \) explicitly as \( f(x) = 0 - \frac{1}{2} x^{-1/2} = -\frac{1}{2 \sqrt{x}} \).
The integral to find is \( \int -f(x) \, dx \). Substitute \( f(x) \) into the integral to get \( \int -\left(-\frac{1}{2 \sqrt{x}}\right) dx = \int \frac{1}{2 \sqrt{x}} \, dx \).
Rewrite the integral in terms of exponents: \( \int \frac{1}{2} x^{-1/2} \, dx \). Use the power rule for integration: \( \int x^{n} \, dx = \frac{x^{n+1}}{n+1} + C \), where \( n \neq -1 \).

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