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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.7.13c

Finding Antiderivatives
In Exercises 1–16, find an antiderivative for each function. Do as many as you can mentally. Check your answers by differentiation.
-sec²(3x/2)

Guida verificata passo dopo passo
1
Recognize that the function given is \(-\sec^{2}\left(\frac{3x}{2}\right)\), which resembles the derivative of the tangent function, since \(\frac{d}{dx}[\tan(u)] = \sec^{2}(u) \cdot \frac{du}{dx}\).
Identify the inner function \(u = \frac{3x}{2}\) and compute its derivative: \(\frac{du}{dx} = \frac{3}{2}\).
Set up the antiderivative integral: \(\int -\sec^{2}\left(\frac{3x}{2}\right) dx\).
Use substitution: let \(u = \frac{3x}{2}\), so \(dx = \frac{2}{3} du\). Rewrite the integral in terms of \(u\): \(\int -\sec^{2}(u) \cdot \frac{2}{3} du = -\frac{2}{3} \int \sec^{2}(u) du\).
Recall that \(\int \sec^{2}(u) du = \tan(u) + C\), so the antiderivative is \(-\frac{2}{3} \tan\left(\frac{3x}{2}\right) + C\).

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Antiderivative (Indefinite Integral)

An antiderivative of a function is another function whose derivative equals the original function. It is also called the indefinite integral and includes a constant of integration since differentiation loses constant terms.
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Introduction to Indefinite Integrals

Derivative of Trigonometric Functions

Knowing the derivatives of basic trig functions like tan(x) and sec(x) is essential. For example, the derivative of tan(x) is sec²(x), which helps in recognizing antiderivatives involving sec² terms.
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Derivatives of Other Inverse Trigonometric Functions

Chain Rule and Substitution

When functions involve compositions like sec²(3x/2), the chain rule applies. To find antiderivatives, substitution reverses the chain rule by adjusting for the inner function's derivative.
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Intro to the Chain Rule
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Analyzing Functions from Derivatives


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Answer the following questions about the functions whose derivatives are given in Exercises 1–14:

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