Domanda del libro di testo
For problems 49–52 use implicit differentiation to find dy/dx at the given point P.
49. 3arctan(x) + arcsin(y) = π/4; P(1, -1)
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Ch. 7 - Transcendental Functions
Hass15th EditionThomas' CalculusISBN: 9780137616077
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TOC.tableOfContents
- Ch. 1 - Functions155
- Ch. 2 - Limits and Continuity240
- Ch. 3 - Derivatives337
- Ch. 4 - Applications of Derivatives293
- Ch. 5 - Integrals41
- Ch. 6 - Applications of Definite Integrals25
- Ch. 7 - Transcendental Functions490
- Ch. 8 - Techniques of Integration399
- Ch. 9 - First-Order Differential Equations66
- Ch. 10 - Infinite Sequences and Series132
- Ch. 11 - Parametric Equations and Polar Coordinates58
Capitolo 7, Problema 7.7.57
Evaluate the integrals in Exercises 41–60.
57. ∫(from 1 to 2)cosh(ln t)/t dt
Guida verificata passo dopo passo1
Recognize the integral to evaluate: \(\int_{1}^{2} \frac{\cosh(\ln t)}{t} \, dt\).
Recall the definition of hyperbolic cosine: \(\cosh x = \frac{e^{x} + e^{-x}}{2}\). Substitute \(x = \ln t\) to rewrite the integrand.
Rewrite the integrand as \(\frac{1}{t} \cdot \frac{e^{\ln t} + e^{-\ln t}}{2} = \frac{1}{2t} (t + \frac{1}{t})\) because \(e^{\ln t} = t\) and \(e^{-\ln t} = \frac{1}{t}\).
Simplify the expression inside the integral to \(\frac{1}{2t} (t + \frac{1}{t}) = \frac{1}{2} \left(1 + \frac{1}{t^{2}}\right)\).
Split the integral into two simpler integrals: \(\frac{1}{2} \int_{1}^{2} 1 \, dt + \frac{1}{2} \int_{1}^{2} \frac{1}{t^{2}} \, dt\), then proceed to integrate each term separately.
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Hyperbolic Cosine Function (cosh)
The hyperbolic cosine function, cosh(x), is defined as (e^x + e^(-x))/2. It is similar to the cosine function but based on exponential functions. Understanding its properties helps simplify expressions involving cosh, especially when combined with logarithmic arguments.
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Percorso guidato
5:53
Graph of Sine and Cosine Function
Logarithmic Functions and Their Properties
The natural logarithm function, ln(t), is the inverse of the exponential function e^x. Key properties, such as ln(ab) = ln(a) + ln(b) and ln(t^n) = n ln(t), allow simplification of integrands involving ln(t). Recognizing how ln(t) interacts with other functions is crucial for integration.
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Percorso guidato
06:21Properties of Functions
Integration Techniques and Substitution
Integration by substitution is a method to simplify integrals by changing variables. Here, substituting u = ln(t) transforms the integral into a more manageable form. Mastery of substitution and recognizing when to apply it is essential for evaluating integrals involving composite functions.
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04:27Substitution With an Extra Variable
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