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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoHass 15th EditionCh. 7 - Transcendental FunctionsProblema 7.5.63
Capitolo 7, Problema 7.5.63

Indeterminate Powers and Products
Find the limits in Exercises 53–68.
63. lim (x → ∞) ((x + 2)/(x - 1))^x

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Identify the limit expression: \(\lim_{x \to \infty} \left( \frac{x + 2}{x - 1} \right)^x\).
Rewrite the base inside the parentheses to express it in a form that approaches 1 as \(x\) approaches infinity. For example, write \(\frac{x + 2}{x - 1} = \frac{x - 1 + 3}{x - 1} = 1 + \frac{3}{x - 1}\).
Recognize that the limit has the indeterminate form \(1^\infty\), which suggests using the exponential and logarithm transformation: rewrite the limit as \(\lim_{x \to \infty} e^{x \ln \left(1 + \frac{3}{x - 1} \right)}\).
Focus on evaluating the exponent limit: \(\lim_{x \to \infty} x \ln \left(1 + \frac{3}{x - 1} \right)\). Use the fact that \(\ln(1 + y) \approx y\) for small \(y\) to simplify the expression inside the limit.
Calculate the simplified limit of the exponent, then substitute back into the exponential function to find the overall limit.

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Limits at Infinity

Limits at infinity describe the behavior of a function as the input variable grows without bound. Understanding how expressions behave as x approaches infinity helps determine the end behavior of functions, which is essential for evaluating limits like ((x + 2)/(x - 1))^x as x → ∞.
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Cases Where Limits Do Not Exist

Indeterminate Forms

Indeterminate forms occur when a limit expression does not directly yield a clear value, such as 1^∞, 0/0, or ∞/∞. Recognizing these forms is crucial because they require special techniques, like logarithms or L'Hôpital's Rule, to resolve the limit properly.
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Exponential Limits and Logarithmic Transformation

When limits involve expressions raised to variable powers, rewriting the expression using logarithms can simplify evaluation. By setting y = f(x)^g(x), taking the natural log, and then applying limit laws, one can find the limit of y by exponentiating the limit of the logarithm.
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