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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.PE.81

In Exercises 79–84, solve for y.
81. 9e^(2y) = = x^2

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Start with the given equation: \(9e^{2y} = x^2\).
Isolate the exponential term by dividing both sides of the equation by 9: \(e^{2y} = \frac{x^2}{9}\).
To solve for \(y\), take the natural logarithm (ln) of both sides to undo the exponential: \(\ln\left(e^{2y}\right) = \ln\left(\frac{x^2}{9}\right)\).
Use the logarithm property \(\ln\left(e^a\right) = a\) to simplify the left side: \(2y = \ln\left(\frac{x^2}{9}\right)\).
Finally, solve for \(y\) by dividing both sides by 2: \(y = \frac{1}{2} \ln\left(\frac{x^2}{9}\right)\).

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