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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 57

In Exercises 51–58, solve each compound inequality. - 3 ≤ (2/3)x - 5 < - 1

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Start by writing the compound inequality clearly: \(-3 \leq \frac{2}{3}x - 5 < -1\).
Add 5 to all three parts of the inequality to isolate the term with \(x\): \(-3 + 5 \leq \frac{2}{3}x - 5 + 5 < -1 + 5\).
Simplify each part: \(2 \leq \frac{2}{3}x < 4\).
Multiply all parts of the inequality by the reciprocal of \(\frac{2}{3}\), which is \(\frac{3}{2}\), to solve for \(x\): \(2 \times \frac{3}{2} \leq x < 4 \times \frac{3}{2}\).
Simplify the multiplication to find the range of \(x\): \(3 \leq x < 6\).

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