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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 57

Solve each equation in Exercises 47–64 by completing the square. x2+3x−1=0x^2 + 3x - 1 = 0

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1
Start with the given quadratic equation: \(x^2 + 3x - 1 = 0\).
Move the constant term to the other side to isolate the \(x\) terms: \(x^2 + 3x = 1\).
To complete the square, take half of the coefficient of \(x\), which is \(\frac{3}{2}\), then square it: \(\left(\frac{3}{2}\right)^2 = \frac{9}{4}\).
Add \(\frac{9}{4}\) to both sides of the equation to maintain equality: \(x^2 + 3x + \frac{9}{4} = 1 + \frac{9}{4}\).
Rewrite the left side as a perfect square trinomial: \(\left(x + \frac{3}{2}\right)^2 = 1 + \frac{9}{4}\), then simplify the right side.

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