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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 71

In Exercises 61–76, solve each absolute value equation or indicate that the equation has no solution. 2|4 - (5/2)x| + 6 = 18

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Start by isolating the absolute value expression. Subtract 6 from both sides of the equation: 2\(\left\)|4 - \(\frac{5}{2}\)x\(\right\)| + 6 - 6 = 18 - 6, which simplifies to 2\(\left\)|4 - \(\frac{5}{2}\)x\(\right\)| = 12.
Next, divide both sides of the equation by 2 to further isolate the absolute value: \(\frac{2\left|4 - \frac{5}{2}\)x\(\right\)|}{2} = \(\frac{12}{2}\), giving \(\left\)|4 - \(\frac{5}{2}\)x\(\right\)| = 6.
Recall that if \(\left\)|A\(\right\)| = B, where B > 0, then A = B or A = -B. Apply this property to get two separate equations: 4 - \(\frac{5}{2}\)x = 6 and 4 - \(\frac{5}{2}\)x = -6.
Solve each equation for x separately. For the first equation, subtract 4 from both sides and then multiply both sides by the reciprocal of \(\frac{5}{2}\) to isolate x. Repeat the process for the second equation.
Check your solutions by substituting them back into the original equation to ensure they satisfy the absolute value equation.

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