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Ch. 3 - Polynomial and Rational Functions
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 9

Among all pairs of numbers whose difference is 14, find a pair whose product is as small as possible. What is the minimum product?

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1
Let the two numbers be \(x\) and \(y\). According to the problem, their difference is 14, so we can write the equation: \(x - y = 14\).
Express one variable in terms of the other using the difference equation. For example, solve for \(x\): \(x = y + 14\).
Write the product of the two numbers as a function of one variable: \(P = x \times y = (y + 14) \times y = y^2 + 14y\).
To find the minimum product, take the derivative of \(P\) with respect to \(y\) and set it equal to zero to find critical points: \(\frac{dP}{dy} = 2y + 14 = 0\).
Solve the derivative equation for \(y\), then substitute back into \(x = y + 14\) to find the corresponding \(x\). Finally, calculate the product \(P = x \times y\) using these values to find the minimum product.

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