Domanda del libro di testo
In Exercises 1–16, divide using long division. State the quotient, and the remainder, r(x). (6x3+13x2−11x−15)/(3x2−x−3)
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Ch. 3 - Polynomial and Rational Functions
Blitzer8th EditionCollege AlgebraISBN: 9780136970514
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TOC.tableOfContents
- Ch. P - Fundamental Concepts of Algebra311
- Ch. 1 - Equations and Inequalities398
- Ch. 2 - Functions and Graphs407
- Ch. 3 - Polynomial and Rational Functions306
- Ch. 4 - Exponential and Logarithmic Functions247
- Ch. 5 - Systems of Equations and Inequalities173
- Ch. 6 - Matrices and Determinants143
- Ch. 7 - Conic Sections124
- Ch. 8 - Sequences, Induction, and Probability251
Capitolo 4, Problema 13
Write an equation that expresses each relationship. Then solve the equation for y. x varies directly as the cube of z and inversely as y.
Guida verificata passo dopo passo1
Identify the given variation relationship: "x varies directly as the cube of z and inversely as y." This means x is proportional to \( z^3 \) and inversely proportional to \( y \).
Write the variation equation using a constant of proportionality \( k \):
\[ x = \frac{k \cdot z^3}{y} \]
To solve for \( y \), multiply both sides of the equation by \( y \) to get rid of the denominator:
\[ x \cdot y = k \cdot z^3 \]
Next, isolate \( y \) by dividing both sides by \( x \):
\[ y = \frac{k \cdot z^3}{x} \]
The equation is now solved for \( y \) in terms of \( x \), \( z \), and the constant \( k \).
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Direct Variation
Direct variation describes a relationship where one variable is proportional to another. If x varies directly as the cube of z, it means x = k * z³ for some constant k, indicating that as z increases, x changes proportionally to z cubed.
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Maximum Turning Points of a Polynomial Function
Inverse Variation
Inverse variation means one variable changes in the opposite way to another. Here, x varies inversely as y, so x = k / y, implying that as y increases, x decreases proportionally, and vice versa.
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Solving for a Variable in an Equation
Solving for y involves manipulating the equation algebraically to isolate y on one side. This requires understanding how to rearrange terms, use inverse operations, and simplify expressions to express y explicitly in terms of x and z.
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Write an equation that expresses each relationship. Then solve the equation for y. x varies directly as the cube root of z and inversely as y.
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