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Ch. 4 - Exponential and Logarithmic Functions
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 5, Problema 95

Solve each equation. 2|ln x|−6=0

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1
Start with the given equation: \(2|\ln x| - 6 = 0\).
Isolate the absolute value expression by adding 6 to both sides: \(2|\ln x| = 6\).
Divide both sides by 2 to solve for the absolute value: \(|\ln x| = 3\).
Recall that \(|A| = B\) means \(A = B\) or \(A = -B\). So, set up two equations: \(\ln x = 3\) and \(\ln x = -3\).
Solve each equation for \(x\) by exponentiating both sides with base \(e\): \(x = e^{3}\) and \(x = e^{-3}\). Remember to check that \(x > 0\) since the natural logarithm is only defined for positive \(x\).

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