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Ch. 4 - Exponential and Logarithmic Functions
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 5, Problema 96

Solve each equation. 3|log x|−6=0

Guida verificata passo dopo passo
1
Start with the given equation: \(3|\log x| - 6 = 0\).
Isolate the absolute value expression by adding 6 to both sides: \(3|\log x| = 6\).
Divide both sides by 3 to solve for the absolute value: \(|\log x| = 2\).
Recall that \(|A| = B\) means \(A = B\) or \(A = -B\). So, set up two equations: \(\log x = 2\) and \(\log x = -2\).
Solve each equation for \(x\) by rewriting in exponential form: \(x = 10^2\) and \(x = 10^{-2}\).

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