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Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 6, Problema 35

In Exercises 31–42, solve by the method of your choice. Identify systems with no solution and systems with infinitely many solutions, using set notation to express their solution sets. 3x - 2y = − 5 4x + y = 8

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Start by writing down the system of equations clearly: 3x - 2y = -5 and 4x + y = 8.
Choose a method to solve the system. Here, substitution or elimination are both good options. For elimination, aim to eliminate one variable by making the coefficients of either x or y opposites.
Multiply the second equation by 2 to align the coefficients of y: 2(4x + y) = 2(8) which gives 8x + 2y = 16.
Add the first equation 3x - 2y = -5 and the new equation 8x + 2y = 16 to eliminate y: (3x + 8x) + (-2y + 2y) = -5 + 16.
Solve the resulting equation for x, then substitute this value back into one of the original equations to find y. Finally, check if the system has one solution, no solution, or infinitely many solutions by analyzing the consistency of the equations.

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