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Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 6, Problema 37

In Exercises 31–42, solve by the method of your choice. Identify systems with no solution and systems with infinitely many solutions, using set notation to express their solution sets. x + 3y = 2 3x + 9y = 6

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Start by writing down the system of equations: x+3y=2 and 3x+9y=6.
Observe that the second equation is a multiple of the first equation. Specifically, multiply the first equation by 3: 3(x + 3y) = 3(2) which simplifies to 3x + 9y = 6.
Since the second equation is exactly the same as the first equation multiplied by 3, the two equations represent the same line, meaning there are infinitely many solutions.
Express the solution set by solving the first equation for x in terms of y: x = 2 - 3y.
Write the solution set in set notation as {(x, y) | x = 2 - 3y, y \, \(\in\) \, \(\mathbb{R}\)}, indicating all points on the line satisfy the system.

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