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Ch.20 - Electrochemistry
Brown - Chemistry: The Central Science 14th Edition
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoBrown 14th EditionCh.20 - ElectrochemistryProblema 104
Capitolo 20, Problema 104

(b) Given the following reduction potentials, calculate the standard emf of the cell: Cd1OH221s2 + 2 e- ¡ Cd1s2 + 2 OH-1aq2 E°red = -0.76 V NiO1OH21s2 + H2O1l2 + e- ¡ Ni1OH221s2 + OH-1aq2 E°red = +0.49 V

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Identify the two half-reactions and their standard reduction potentials: Cd(OH)2(s) + 2e^- -> Cd(s) + 2OH^-(aq) with E°_red = -0.76 V and NiO(OH)(s) + H2O(l) + e^- -> Ni(OH)2(s) + OH^-(aq) with E°_red = +0.49 V.
Determine which half-reaction will be the oxidation and which will be the reduction. The half-reaction with the more positive reduction potential will proceed as the reduction, and the other will be reversed to act as the oxidation.
Reverse the half-reaction with the less positive (or more negative) reduction potential to represent oxidation. This means reversing the Cd(OH)2 half-reaction: Cd(s) + 2OH^-(aq) -> Cd(OH)2(s) + 2e^- and changing its sign to E°_ox = +0.76 V.
Calculate the standard cell potential (E°_cell) by adding the standard reduction potential of the reduction half-reaction to the standard oxidation potential of the oxidation half-reaction: E°_cell = E°_red (NiO(OH)) + E°_ox (Cd).
Substitute the values into the equation: E°_cell = +0.49 V + (+0.76 V) and simplify to find the standard emf of the cell.

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Standard Electrode Potentials

Standard electrode potentials (E°) are measured voltages that indicate the tendency of a chemical species to be reduced, with more positive values signifying a greater likelihood of reduction. These values are determined under standard conditions (1 M concentration, 1 atm pressure, and 25°C) and are essential for calculating the overall cell potential in electrochemical cells.
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Standard Cell Potential

Cell Potential Calculation

The standard electromotive force (emf) of an electrochemical cell can be calculated using the formula E°cell = E°cathode - E°anode. In this context, the cathode is where reduction occurs, and the anode is where oxidation takes place. By substituting the given reduction potentials into this formula, one can determine the overall cell potential.
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Standard Cell Potential

Oxidation and Reduction Reactions

In electrochemistry, oxidation refers to the loss of electrons, while reduction refers to the gain of electrons. Each half-reaction in a redox process involves either oxidation or reduction. Understanding which species is oxidized and which is reduced is crucial for correctly identifying the anode and cathode in a cell, which directly impacts the calculation of the cell potential.
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Oxidation and Reduction Reactions
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Domanda del libro di testo

A voltaic cell is constructed that uses the following half-cell reactions:

Cu+(aq) + e- → Cu(s)

I2(s) + 2 e- → 2 I-(aq)

The cell is operated at 298 K with [Cu+] = 0.25 M and [I-] = 0.035 M.

(a) Determine E for the cell at these concentrations.

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Domanda del libro di testo

A voltaic cell is constructed that uses the following half-cell reactions:

Cu+(aq) + e- → Cu(s)

I2(s) + 2 e- → 2 I-(aq)

The cell is operated at 298 K with [Cu+] = 0.25 M and [I-] = 0.035 M.

(b) Which electrode is the anode of the cell?

(c) Is the answer to part (b) the same as it would be if the cell were operated under standard conditions?

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