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Ch.1 - Matter, Measurement & Problem Solving
Tro - Chemistry: A Molecular Approach 5th Edition
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Tutti i libri di testoTro 5th EditionCh.1 - Matter, Measurement & Problem SolvingProblema 70
Capitolo 1, Problema 70

Acetone (nail polish remover) has a density of 0.7857 g/cm3. a. What is the mass in g of 28.56 mL of acetone? b. What is the volume in mL of 6.54 g of acetone?

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**Step 1:** Understand the relationship between mass, volume, and density. The formula to use is: \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \).
**Step 2:** For part (a), rearrange the formula to solve for mass: \( \text{Mass} = \text{Density} \times \text{Volume} \).
**Step 3:** Substitute the given values for density (0.7857 g/cm³) and volume (28.56 mL) into the formula to find the mass. Remember that 1 mL = 1 cm³.
**Step 4:** For part (b), rearrange the formula to solve for volume: \( \text{Volume} = \frac{\text{Mass}}{\text{Density}} \).
**Step 5:** Substitute the given values for mass (6.54 g) and density (0.7857 g/cm³) into the formula to find the volume.

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Density

Density is defined as the mass of a substance per unit volume, typically expressed in grams per cubic centimeter (g/cm³). It is a crucial property that helps determine how much mass is contained in a given volume of a substance. In this question, the density of acetone is used to convert between mass and volume, allowing us to calculate the mass of a specific volume of acetone and vice versa.
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Density Concepts

Mass-Volume Relationship

The mass-volume relationship is a fundamental concept in chemistry that describes how mass and volume are interrelated through density. The formula used to express this relationship is: mass = density × volume. This relationship is essential for solving problems that involve converting between mass and volume, as seen in the calculations for acetone in the question.
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Relationship of Volume and Moles Example

Unit Conversion

Unit conversion is the process of converting a quantity expressed in one set of units to another set of units. In chemistry, it is often necessary to convert between different units of mass (grams) and volume (milliliters or liters). Understanding how to perform these conversions accurately is vital for solving problems involving measurements, such as calculating the mass of acetone from its volume and density.
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Conversion Factors
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