Domanda del libro di testo
Acetone (nail polish remover) has a density of 0.7857 g/cm3. a. What is the mass in g of 28.56 mL of acetone? b. What is the volume in mL of 6.54 g of acetone?
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Ch.1 - Matter, Measurement & Problem Solving
Tro5th EditionChemistry: A Molecular ApproachISBN: 9780134874371
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TOC.tableOfContents
- Ch.1 - Matter, Measurement & Problem Solving117
- Ch.2 - Atoms & Elements106
- Ch.3 - Molecules and Compounds128
- Ch.4 - Chemical Reactions and Chemical Quantities56
- Ch.5 - Introduction to Solutions and Aqueous Solutions84
- Ch.6 - Gases112
- Ch.7 - Thermochemistry96
- Ch.8 - The Quantum-Mechanical Model of the Atom60
- Ch.9 - Periodic Properties of the Elements86
- Ch.10 - Chemical Bonding I: The Lewis Model91
- Ch.11 - Chemical Bonding II: Molecular Shapes, VSEPR & MO Theory85
- Ch.12 - Liquids, Solids & Intermolecular Forces51
- Ch.13 - Solids & Modern Materials48
- Ch.14 - Solutions93
- Ch.15 - Chemical Kinetics114
- Ch.16 - Chemical Equilibrium68
- Ch.17 - Acids and Bases137
- Ch.18 - Aqueous Ionic Equilibrium154
- Ch.19 - Free Energy & Thermodynamics91
- Ch.20 - Electrochemistry105
- Ch.21 - Radioactivity & Nuclear Chemistry74
- Ch.22 - Organic Chemistry141
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Capitolo 1, Problema 69a
Ethylene glycol (antifreeze) has a density of 1.11 g/cm3. a. What is the mass in g of 417 mL of ethylene glycol? b. What is the volume in L of 4.1 kg of ethylene glycol?
Guida verificata passo dopo passo1
1. To find the mass of ethylene glycol, you need to use the formula for density, which is mass divided by volume (density = mass/volume). In this case, you know the density (1.11 g/cm3) and the volume (417 mL), and you need to find the mass. Since 1 cm3 is equivalent to 1 mL, you can directly multiply the density by the volume to get the mass. So, the mass of ethylene glycol is 1.11 g/cm3 * 417 mL.
2. To convert the mass from grams to kilograms, remember that 1 kg = 1000 g. So, divide the mass you found in step 1 by 1000 to get the mass in kilograms.
3. To find the volume of ethylene glycol, you again use the formula for density (density = mass/volume). This time, you know the density (1.11 g/cm3) and the mass (4.1 kg), and you need to find the volume. First, convert the mass from kilograms to grams (since the density is given in g/cm3). Then, rearrange the density formula to solve for volume (volume = mass/density). So, the volume of ethylene glycol is 4.1 kg * 1000 g/kg / 1.11 g/cm3.
4. To convert the volume from cm3 to liters, remember that 1 L = 1000 cm3. So, divide the volume you found in step 3 by 1000 to get the volume in liters.
5. Now you have the mass of 417 mL of ethylene glycol in grams and the volume of 4.1 kg of ethylene glycol in liters.
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Density
Density is defined as the mass of a substance per unit volume, typically expressed in grams per cubic centimeter (g/cm³) or kilograms per liter (kg/L). It is a crucial property that helps in determining how much mass is contained in a given volume of a substance. In this question, the density of ethylene glycol is used to calculate the mass from a known volume and vice versa.
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Percorso guidato
01:56
Density Concepts
Mass-Volume Relationship
The mass-volume relationship is a fundamental concept in chemistry that describes how mass and volume are interrelated through density. The formula used is mass = density × volume. This relationship allows for the conversion between mass and volume when the density of a substance is known, which is essential for solving the parts of the question regarding ethylene glycol.
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Percorso guidato
01:09Relationship of Volume and Moles Example
Unit Conversion
Unit conversion is the process of converting a quantity expressed in one set of units to another. In this question, it is necessary to convert between milliliters (mL) and liters (L) as well as between grams (g) and kilograms (kg). Understanding how to perform these conversions is vital for accurately answering the question and ensuring that all measurements are in compatible units.
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Percorso guidato
01:56Conversion Factors
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