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Ch.9 Solutions
McMurry - Fundamentals of General, Organic, and Biological Chemistry 8th Edition
McMurry8th EditionFundamentals of General, Organic, and Biological ChemistryISBN: 9780134015187Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoMcMurry 8th EditionCh.9 SolutionsProblema 63
Capitolo 9, Problema 63

An aqueous solution that contains 285 ppm of potassium nitrate (KNO3) is being used to feed plants in a garden. What volume of this solution is needed to prepare 2.0 L of a solution that is 75 ppm in KNO3?

Guida verificata passo dopo passo
1
Step 1: Understand the concept of ppm (parts per million). It is a way to express concentration, where 1 ppm means 1 part of solute per 1,000,000 parts of solution. In this problem, the concentration of potassium nitrate (KNO₃) is given in ppm for two solutions: 285 ppm (initial solution) and 75 ppm (final solution).
Step 2: Use the dilution equation to relate the concentrations and volumes of the solutions. The dilution equation is: C1V1 = C2V2, where C1 and C2 are the initial and final concentrations, and V1 and V2 are the initial and final volumes, respectively.
Step 3: Substitute the known values into the dilution equation. Here, C1 = 285 ppm, C2 = 75 ppm, and V2 = 2.0 L. The equation becomes: 285V1 = 75(2.0).
Step 4: Solve for V1, the volume of the initial solution needed. Rearrange the equation to isolate V1: V1 = (75(2.0))/285.
Step 5: Perform the calculation to determine the value of V1. This will give you the volume of the 285 ppm solution required to prepare 2.0 L of a 75 ppm solution.

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Parts Per Million (ppm)

Parts per million (ppm) is a unit of measurement that expresses the concentration of a substance in a solution. It indicates how many parts of a solute are present in one million parts of the solution. For example, a concentration of 285 ppm means that there are 285 grams of solute in one million grams of solution, which is crucial for understanding the dilution process in this question.
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Parts per Million (ppm) Concept 1

Dilution

Dilution is the process of reducing the concentration of a solute in a solution, typically by adding more solvent. In this context, to prepare a 75 ppm solution from a 285 ppm solution, one must calculate the appropriate volume of the concentrated solution to mix with water. The dilution formula, C1V1 = C2V2, where C is concentration and V is volume, is essential for solving this problem.
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Dilutions

Concentration Calculation

Concentration calculation involves determining the amount of solute in a given volume of solution. In this scenario, it is necessary to calculate how much of the 285 ppm solution is required to achieve a final concentration of 75 ppm in a total volume of 2.0 L. This requires understanding the relationship between the initial and final concentrations and the volumes involved.
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Percent Concentrations Concept 1
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