-the-standard-equation-x-h2a2-y-k2b2-1-what-point-is-the-center-of-the-hyperbola

Question

In the standard equation (x−h)2a2−(y−k)2b2=1\frac{$$(x-h)^2$$}{$$a^2$$}-\frac{$$(y-k)^2$$}{$$b^2$$}=1, what point is the center of the hyperbola?

Accepted Answer

(h,k)(h, k)

Answer

(a,b)(a, b)

Answer

(−h,−k)(-h, -k)

Answer

(a2,$$b2)(a^2$$, $$b^2) $$

In the standard equation (x−h)2a2−(y−k)2b2=1\(\frac{(x-h)^2}{a^2}\)-\(\frac{(y-k)^2}{b^2}\)=1, what point is the center of the hyperbola?