f-the-parabola-that-has-vertex-3-2-opens-upward-and-passes-through-the-point-5-6

Question

Find the vertex form of the vertical parabola with vertex (3,−2)(3, -2) that passes through the point (5,6)(5, 6).

Accepted Answer

y=2(x−3)2−2y = 2(x − $$3)^2$$ − 2

Answer

x=2(y+2)2+2x = 2(y + $$2)^2 + 2 $$

Answer

y=2(x−3)2+2y=$$2(x-3)^2+2 $$

Answer

y=12(x+3)2−2{\displaystyle y=\$$frac12(x+3)^2-2$$}