Domanda del libro di testo
Design an acid–base extraction scheme to separate a mixture of the basic amine N,N-dimethylaniline and naphthalene.
1353
views
Ch. 4 - Acids and Bases/Electron Flow
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471
Non è quello che usi tu?Cambia libro di testoScegli un libro di testo diverso
TOC.tableOfContents
- Ch. 2 - General Chemistry Translated: Finding the Electrons114
- Ch. 3 - Alkanes and Cycloalkanes: Properties and Conformational Analysis109
- Ch. 4 - Acids and Bases/Electron Flow144
- Ch. 5 - Chemical Reaction Analysis: Thermodynamics and Kinetics118
- Ch. 6 - Stereoisomerism: Arrangement of Atoms in Space112
- Ch. 7 - Principles of Green (Organic) Chemistry3
- Ch. 8 - Alkenes 1: Properties and Electrophilic Additions158
- Ch. 9 - Alkenes 2: Oxidation and Reduction150
- Ch. 10 - Alkynes: Electrophilic Addition and Redox Reactions101
- Ch. 11 - Properties and Synthesis of Alkyl Halides: Radical Reactions108
- Ch. 12 - Substitution and Elimination: Reactions of Haloalkanes172
- Ch. 13 - Alcohols, Ethers and Related Compounds: Substitution and Elimination239
- Ch. 14 - Structural Identification 1: Infrared Spectroscopy and Mass Spectrometry54
- Ch. 15 - Structural Identification 2: Nuclear Magnetic Resonance Spectroscopy93
- Ch. 16 - Metals in Organic Chemistry48
- Ch. 17 - Carbonyl Addition Reactions: Aldehydes and Ketones45
- Ch. 18 - Nucleophilic Acyl Substitution 1: Carboxylic Acids18
- Ch. 19 - Nucleophilic Acyl Substitution 2: Carboxylic Acid Derivatives39
- Ch. 20 - Enolates: Carbonyl Addition and Substitution13
- Ch. 21 - Conjugated Systems 1: Stability and Addition Reactions56
- Ch. 22 - Conjugated Systems 2: Pericyclic Reactions54
- Ch. 23 - Benzene 1: Aromatic Stability and Substitution Reactions64
- Ch. 24 - Benzene 2: Reactions Influenced by the Aromatic Ring62
- Ch. 25 - Amines: Structure, Reactions, and Synthesis27
- Ch. 26 - Amino Acids, Proteins, and Peptide Synthesis9
- Ch. 27 - Carbohydrates, Nucleic Acids, and Lipids54
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 29
Given the following Keq values, how much stronger of a base is acetate (CH3CO2-) than chloride (Cl⁻)?
Guida verificata passo dopo passo1
Step 1: Understand the relationship between K_eq and base strength. The equilibrium constant (K_eq) is related to the acid dissociation constant (K_a) of the conjugate acids. A stronger base corresponds to a weaker conjugate acid, which has a smaller K_a value.
Step 2: Identify the conjugate acids of the bases in question. Acetate (CH₃CO⁻₂) is the conjugate base of acetic acid (CH₃COOH), and chloride (Cl⁻) is the conjugate base of hydrochloric acid (HCl).
Step 3: Use the formula K_a = K_eq for the dissociation of the conjugate acid. Compare the K_a values of acetic acid and hydrochloric acid to determine the relative base strength of acetate and chloride.
Step 4: Calculate the ratio of the K_a values. The relative base strength can be determined by comparing the inverse of the K_a values (since base strength is inversely proportional to acid strength). Use the formula: \( \text{Relative base strength} = \frac{K_{a, \text{HCl}}}{K_{a, \text{CH₃COOH}}} \).
Step 5: Interpret the result. The larger the ratio, the stronger acetate is as a base compared to chloride. This ratio quantifies how much stronger acetate is as a base than chloride.
Risposta video verificata per un problema simile:
Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
4mConcetti chiave
Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.
Equilibrium Constant (K_eq)
The equilibrium constant (K_eq) quantifies the ratio of the concentrations of products to reactants at equilibrium for a reversible reaction. A higher K_eq value indicates that the products are favored, suggesting a stronger tendency for the reaction to proceed in that direction. In the context of acids and bases, K_eq can help determine the relative strengths of different bases.
Video consigliato:
02:19
The relationship between equilibrium constant and pKa.
Acidity and Basicity
Acidity refers to the tendency of a substance to donate protons (H⁺), while basicity refers to the ability to accept protons. The strength of a base can be inferred from the K_eq of its conjugate acid; a stronger base corresponds to a weaker conjugate acid. Understanding the relationship between acids and bases is crucial for comparing the basicity of acetate and chloride.
Video consigliato:
06:21Understanding the difference between basicity and nucleophilicity.
Conjugate Acid-Base Pairs
Conjugate acid-base pairs consist of two species that differ by the presence of a proton. For example, acetate (CH₃CO⁻₂) is the conjugate base of acetic acid (CH₃COOH), while chloride (Cl⁻) is the conjugate base of hydrochloric acid (HCl). The strength of the conjugate acids can be compared using their K_a values, which directly influences the basicity of their corresponding bases.
Video consigliato:
Percorso guidato
2:56Base Pairing Concept 1
Pratica correlata
Domanda del libro di testo
Given the following Keq values, how much stronger of an acid is methanol (CH3OH) than acetylene (HC≡CH)?
1127
views
Domanda del libro di testo
Hydrogen gas (H2) has a relatively high pKa value. Is it a stable or unstable acid? Do you expect it to participate in acid–base reactions?
1549
views
Domanda del libro di testo
An unknown acid (HA) has been identified as very strong. What does this tell you about the stability of the conjugate base, A⁻? Is it strong or weak? Is it reactive or unreactive?
1100
views
Domanda del libro di testo
Given that the indicated pKa values correspond to the acid dissociation reactions shown, calculate the ratio of acid to conjugate base for the reactions shown.
(a)
925
views
Domanda del libro di testo
Given that the indicated pKa values correspond to the acid dissociation reactions shown, calculate the ratio of acid to conjugate base for the reactions shown.
(b)
1261
views