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Ch. 9 - Alkenes 2: Oxidation and Reduction
Mullins - Organic Chemistry: A Learner Centered Approach 1st Edition
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 25

Show an arrow-pushing mechanism for reactions 1–4 in Figure 9.37.
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Step 1: Epoxidation - The alkene reacts with the persulfonic acid (R-SO3H) to form an epoxide. The oxygen from the persulfonic acid is transferred to the double bond of the alkene, forming a three-membered cyclic ether (epoxide). This step involves the movement of electrons from the double bond to the oxygen atom.
Step 2: Acid-base reaction - The epoxide undergoes protonation by the sulfonic acid (R-SO3H), which donates a proton (H+) to the oxygen atom of the epoxide. This protonation makes the epoxide more electrophilic and susceptible to nucleophilic attack.
Step 3: Epoxide opening - Water (H2O) acts as a nucleophile and attacks the protonated epoxide. The nucleophilic attack leads to the opening of the three-membered ring, resulting in the formation of a diol (two hydroxyl groups on adjacent carbons). This step involves the movement of electrons from the water molecule to the carbon atom of the epoxide.
Step 4: Acid-base reaction - The newly formed diol undergoes deprotonation by the sulfonic acid, regenerating the sulfonic acid and stabilizing the diol product. This step involves the transfer of a proton from the diol to the sulfonic acid.
Step 5: Regeneration of persulfonic acid - Hydrogen peroxide (H2O2) reacts with the sulfonic acid to regenerate the persulfonic acid (R-SO3H), completing the catalytic cycle. This step ensures that the catalyst is available for further reactions.

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