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Ch.11 - Reactions of Alcohols
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Non è quello che usi tu?Cambia libro di testo
Capitolo 11, Problema 55b

Propose mechanisms for the following reactions. In most cases, more products are formed than are shown here. You only need to explain the formation of the products shown, however.
(b) Chemical reaction diagram showing dehydration of an alcohol to form alkenes, with reactants and products labeled.

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Step 1: Analyze the starting material and reaction conditions. The starting material is an alcohol with a double bond in a cyclohexane ring. The reaction conditions include H2SO4 (sulfuric acid) and heat, which suggest an acid-catalyzed dehydration reaction to form alkenes.
Step 2: Protonation of the alcohol group. The hydroxyl group (-OH) is protonated by H2SO4, converting it into a better leaving group (water). This step increases the electrophilicity of the carbon attached to the hydroxyl group.
Step 3: Formation of a carbocation intermediate. After the departure of water, a carbocation is formed at the carbon where the hydroxyl group was attached. The stability of the carbocation is enhanced by resonance with the double bond in the cyclohexane ring.
Step 4: Rearrangement of the carbocation. A hydride shift or alkyl shift may occur to form a more stable carbocation. In this case, the carbocation rearranges to form a bicyclic structure, which is stabilized by conjugation with the double bond.
Step 5: Elimination to form the products. A proton is removed from a neighboring carbon by the conjugate base (HSO4-), leading to the formation of the double bonds in the final products. Two different alkenes are formed due to the possibility of elimination occurring at different positions, resulting in the two products shown.

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