Domanda del libro di testo
Hydration of alkynes (via oxymercuration) gives good yields of single compounds only with symmetrical or terminal alkynes. Show what the products would be from hydration of each compound.
a. hex-3-yne
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Ch. 18 - Ketones and Aldehydes
Wade9th EditionOrganic ChemistryISBN: 9780135213728
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TOC.tableOfContents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
Capitolo 18, Problema 64c
Hydration of alkynes (via oxymercuration) gives good yields of single compounds only with symmetrical or terminal alkynes. Show what the products would be from hydration of each compound.
c. hex-1-yne
Guida verificata passo dopo passo1
Identify the type of alkyne: Hex-1-yne is a terminal alkyne because the triple bond is located at the first carbon of the chain.
Understand the reaction mechanism: Hydration of alkynes via oxymercuration involves the addition of water (H₂O) across the triple bond in the presence of a mercuric ion catalyst (Hg²⁺) and an acid (H₂SO₄). This reaction follows Markovnikov's rule, where the hydroxyl group (-OH) attaches to the more substituted carbon.
Predict the intermediate: The initial addition of water forms an enol intermediate (a compound with a hydroxyl group attached to a carbon-carbon double bond). For hex-1-yne, the enol will have the hydroxyl group on the second carbon.
Account for tautomerization: The enol intermediate is unstable and undergoes keto-enol tautomerization, where the hydroxyl group is converted into a carbonyl group (C=O). This results in the formation of a ketone. For hex-1-yne, the ketone formed will be 2-hexanone.
Summarize the product: The hydration of hex-1-yne via oxymercuration yields 2-hexanone as the final product, following the Markovnikov addition and subsequent tautomerization.
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Hydration of Alkynes
Hydration of alkynes involves the addition of water (H2O) across the triple bond of an alkyne, typically in the presence of a catalyst. This reaction can lead to the formation of enols, which can subsequently tautomerize to form ketones or aldehydes. The regioselectivity of the reaction is influenced by the structure of the alkyne, particularly whether it is symmetrical or terminal.
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09:11
Alkyne Hydration
Oxymercuration-Demercuration
Oxymercuration-demercuration is a two-step reaction used to hydrate alkenes and alkynes. In the first step, mercuric acetate reacts with the alkyne to form a mercurial intermediate, which is then treated with water to yield an alcohol. The second step involves the removal of the mercury group, typically using sodium borohydride, resulting in the formation of the final alcohol product.
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05:General properties of oxymercuration-reduction.
Terminal vs. Internal Alkynes
Terminal alkynes have a triple bond at the end of the carbon chain, while internal alkynes have the triple bond between two carbon atoms. The distinction is crucial in hydration reactions, as terminal alkynes typically yield aldehydes or ketones upon hydration, while internal alkynes can lead to more complex products. In the case of hex-1-yne, being a terminal alkyne, the hydration will produce a specific ketone or aldehyde based on the reaction conditions.
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02:43Anti-Markovnikov addition of alcohols to terminal alkynes yields aldehydes
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