An 8.0-cm-diameter, 400 g solid sphere is released from rest at the top of a 2.1-m-long, 25 incline. It rolls, without slipping, to the bottom. What fraction of its kinetic energy is rotational?
Ch 12: Rotation of a Rigid Body
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Non è quello che usi tu?Cambia libro di testo
Capitolo 12, Problema 39
Vector A = 3î+ĵ and vector B= 3î - 2ĵ + 2k. What is the cross product A ✕ B?
Guida verificata passo dopo passo1
Step 1: Recall the formula for the cross product of two vectors. The cross product \( \mathbf{A} \times \mathbf{B} \) is calculated using the determinant of a 3x3 matrix: \( \mathbf{A} \times \mathbf{B} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ A_x & A_y & A_z \\ B_x & B_y & B_z \end{vmatrix} \), where \( \mathbf{i}, \mathbf{j}, \mathbf{k} \) are the unit vectors, and \( A_x, A_y, A_z \) and \( B_x, B_y, B_z \) are the components of vectors \( \mathbf{A} \) and \( \mathbf{B} \), respectively.
Step 2: Identify the components of \( \mathbf{A} \) and \( \mathbf{B} \). From the problem, \( \mathbf{A} = 3\mathbf{i} + \mathbf{j} \), so \( A_x = 3, A_y = 1, A_z = 0 \). Similarly, \( \mathbf{B} = 3\mathbf{i} - 2\mathbf{j} + 2\mathbf{k} \), so \( B_x = 3, B_y = -2, B_z = 2 \).
Step 3: Write the determinant for the cross product. Substitute the components into the determinant: \( \mathbf{A} \times \mathbf{B} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 3 & 1 & 0 \\ 3 & -2 & 2 \end{vmatrix} \).
Step 4: Expand the determinant. Use cofactor expansion along the first row: \( \mathbf{A} \times \mathbf{B} = \mathbf{i} \begin{vmatrix} 1 & 0 \\ -2 & 2 \end{vmatrix} - \mathbf{j} \begin{vmatrix} 3 & 0 \\ 3 & 2 \end{vmatrix} + \mathbf{k} \begin{vmatrix} 3 & 1 \\ 3 & -2 \end{vmatrix} \).
Step 5: Compute the 2x2 determinants. For each term: \( \begin{vmatrix} 1 & 0 \\ -2 & 2 \end{vmatrix} = (1)(2) - (0)(-2) = 2 \), \( \begin{vmatrix} 3 & 0 \\ 3 & 2 \end{vmatrix} = (3)(2) - (0)(3) = 6 \), and \( \begin{vmatrix} 3 & 1 \\ 3 & -2 \end{vmatrix} = (3)(-2) - (1)(3) = -9 \). Substitute these into the expression to find the cross product.

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Vector Operations
Vector operations involve mathematical manipulations of vectors, including addition, subtraction, and multiplication. The cross product is a specific operation that takes two vectors and produces a third vector that is perpendicular to the plane formed by the original vectors. Understanding how to perform these operations is essential for solving problems involving vectors.
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Operations with Significant Figures
Cross Product
The cross product of two vectors A and B, denoted as A × B, results in a vector that is orthogonal to both A and B. The magnitude of the cross product is given by |A||B|sin(θ), where θ is the angle between the two vectors. The direction of the resulting vector is determined by the right-hand rule, which is crucial for visualizing the orientation of the cross product.
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Coordinate System
In physics, vectors are often represented in a three-dimensional Cartesian coordinate system, defined by the unit vectors î, ĵ, and k. Each vector can be expressed in terms of its components along these axes. Understanding how to manipulate vectors in this coordinate system is vital for calculating operations like the cross product, as it allows for clear representation and computation of vector components.
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