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Ch 13: Newton's Theory of Gravity
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Non è quello che usi tu?Cambia libro di testo
Capitolo 13, Problema 5

What is the force of attraction between a 50 kg woman and a 70 kg man sitting 1.0 m apart?

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Step 1: Identify the formula for gravitational force. The force of attraction between two masses is given by Newton's law of universal gravitation: F=Gm1m2r2, where G is the gravitational constant, m1 and m2 are the masses, and r is the distance between them.
Step 2: Substitute the known values into the formula. The gravitational constant G is approximately 6.674×10-11⁢N⁢m2/kg2. The masses are m1=50 kg and m2=70 kg, and the distance is r=1.0 m.
Step 3: Plug the values into the formula: F=6.674×10-11⁢50⁢701.02. This step involves substituting the values for G, m1, m2, and r into the equation.
Step 4: Simplify the numerator. Multiply 6.674×10-11 by 50 and 70 to calculate the product in the numerator.
Step 5: Divide the result by the square of the distance. Since r=1.0, the square of the distance is 1.02. Perform the division to find the force of attraction.

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Newton's Law of Universal Gravitation

Newton's Law of Universal Gravitation states that every point mass attracts every other point mass in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. This law can be mathematically expressed as F = G(m1*m2)/r^2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses, and r is the distance between them.
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