Unpolarized light with intensity 350 W/m2 passes first through a polarizing filter with its axis vertical, then through a second polarizing filter. It emerges from the second filter with intensity 131 W/m2. What is the angle from vertical of the axis of the second polarizing filter?
Ch 31: Electromagnetic Fields and Waves
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Non è quello che usi tu?Cambia libro di testo
Capitolo 31, Problema 18
A radio receiver can detect signals with electric field amplitudes as small as 300 μV/m. What is the intensity of the smallest detectable signal?
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Understand the relationship between the electric field amplitude and intensity. The intensity \( I \) of an electromagnetic wave is related to the electric field amplitude \( E \) by the formula: \( I = \frac{1}{2} \varepsilon_0 c E^2 \), where \( \varepsilon_0 \) is the permittivity of free space (\( 8.85 \times 10^{-12} \ \text{F/m} \)) and \( c \) is the speed of light in a vacuum (\( 3.00 \times 10^8 \ \text{m/s} \)).
Convert the given electric field amplitude \( E \) from microvolts per meter (\( \mu \text{V/m} \)) to volts per meter (\( \text{V/m} \)). Since \( 1 \ \mu \text{V/m} = 10^{-6} \ \text{V/m} \), the given value of \( 300 \ \mu \text{V/m} \) becomes \( 300 \times 10^{-6} \ \text{V/m} \).
Substitute the values of \( \varepsilon_0 \), \( c \), and the converted \( E \) into the intensity formula: \( I = \frac{1}{2} \varepsilon_0 c E^2 \).
Simplify the expression by squaring the electric field amplitude \( E \) and multiplying it with \( \varepsilon_0 \) and \( c \). Then divide the result by 2 to find the intensity.
Ensure the units are consistent throughout the calculation, and the final intensity \( I \) will be in watts per square meter (\( \text{W/m}^2 \)).

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Electric Field Amplitude
Electric field amplitude refers to the maximum strength of an electric field, measured in volts per meter (V/m). In the context of radio signals, it indicates how strong the electric field component of the electromagnetic wave is. A higher amplitude means a stronger signal, which is easier for a receiver to detect.
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Percorso guidato
Intro to Electric Fields
Intensity of a Signal
The intensity of a signal is defined as the power per unit area carried by the wave, typically measured in watts per square meter (W/m²). It is proportional to the square of the electric field amplitude. Understanding this relationship is crucial for calculating the intensity from the given electric field amplitude.
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Wave Intensity
Relationship Between Electric Field and Intensity
The intensity (I) of an electromagnetic wave is related to the electric field amplitude (E) by the equation I = (E²)/(Z), where Z is the impedance of free space (approximately 377 ohms). This relationship allows us to convert the electric field amplitude of the detected signal into its corresponding intensity, which is essential for understanding the signal's detectability.
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Relationships Between Force, Field, Energy, Potential
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