Domanda del libro di testo
What is the radius of a hydrogen atom whose electron moves at 7.3×105 m/s?
1390
views
Ch 38: Quantization
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796
Non è quello che usi tu?Cambia libro di testoScegli un libro di testo diverso
TOC.tableOfContents
- Ch 01: Concepts of Motion35
- Ch 02: Kinematics in One Dimension75
- Ch 03: Vectors and Coordinate Systems58
- Ch 04: Kinematics in Two Dimensions60
- Ch 05: Force and Motion23
- Ch 06: Dynamics I: Motion Along a Line53
- Ch 07: Newton's Third Law27
- Ch 08: Dynamics II: Motion in a Plane52
- Ch 09: Work and Kinetic Energy56
- Ch 10: Interactions and Potential Energy50
- Ch 11: Impulse and Momentum56
- Ch 12: Rotation of a Rigid Body71
- Ch 13: Newton's Theory of Gravity52
- Ch 14: Fluids and Elasticity44
- Ch 15: Oscillations55
- Ch 16: Traveling Waves37
- Ch 17: Superposition39
- Ch 18: A Macroscopic Description of Matter53
- Ch 19: Work, Heat, and the First Law of Thermodynamics60
- Ch 20: The Micro/Macro Connection53
- Ch 21: Heat Engines and Refrigerators34
- Ch 22: Electric Charges and Forces40
- Ch 23: The Electric Field39
- Ch 24: Gauss' Law32
- Ch 25: The Electric Potential63
- Ch 26: Potential and Field57
- Ch 27: Current and Resistance42
- Ch 28: Fundamentals of Circuits39
- Ch 29: The Magnetic Field47
- Ch 30: Electromagnetic Induction60
- Ch 31: Electromagnetic Fields and Waves32
- Ch 32: AC Circuits63
- Ch 33: Wave Optics32
- Ch 34: Ray Optics57
- Ch 35: Optical Instruments30
- Ch 36: Special Relativity38
- Ch 37: The Foundations of Modern Physics25
- Ch 38: Quantization49
- Ch 39: Wave Functions and Uncertainty31
- Ch 40: One-Dimensional Quantum Mechanics35
- Ch 41: Atomic Physics18
- Ch 42: Nuclear Physics27
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Non è quello che usi tu?Cambia libro di testo
Capitolo 38, Problema 36b
A ruby laser emits an intense pulse of light that lasts a mere 10 ns. The light has a wavelength of 690 nm, and each pulse has an energy of 500 mJ. What is the rate of photon emission, in photons per second, during the 10 ns that the laser is 'on'?
Guida verificata passo dopo passo1
Determine the energy of a single photon using the formula: \( E_{photon} = \frac{hc}{\lambda} \), where \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{J·s} \)), \( c \) is the speed of light (\( 3.00 \times 10^8 \; \text{m/s} \)), and \( \lambda \) is the wavelength of the light (\( 690 \, \text{nm} = 690 \times 10^{-9} \; \text{m} \)).
Calculate the total number of photons emitted in one pulse by dividing the total energy of the pulse by the energy of a single photon: \( N = \frac{E_{pulse}}{E_{photon}} \), where \( E_{pulse} = 500 \, \text{mJ} = 500 \times 10^{-3} \, \text{J} \).
Determine the duration of the pulse in seconds: \( t = 10 \; \text{ns} = 10 \times 10^{-9} \; \text{s} \).
Calculate the rate of photon emission by dividing the total number of photons emitted by the duration of the pulse: \( R = \frac{N}{t} \), where \( N \) is the total number of photons and \( t \) is the pulse duration.
Express the final result for the rate of photon emission in photons per second, ensuring all units are consistent and properly simplified.
Risposta video verificata per un problema simile:
Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Concetti chiave
Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.
Photon Energy
The energy of a single photon can be calculated using the equation E = hc/λ, where E is the energy, h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength in meters. For a ruby laser emitting light at 690 nm, this formula allows us to determine the energy of each photon emitted during the laser pulse.
Video consigliato:
Percorso guidato
04:10
Intro to Energy & Types of Energy
Pulse Duration
The pulse duration refers to the time interval during which the laser emits light. In this case, the ruby laser emits light for 10 nanoseconds (ns), which is 10 x 10^-9 seconds. Understanding the duration is crucial for calculating the total number of photons emitted during this brief period, as it directly influences the rate of emission.
Video consigliato:
Percorso guidato
04:49Example 1
Photon Emission Rate
The photon emission rate is the number of photons emitted per second. It can be calculated by dividing the total energy emitted during the pulse by the energy of a single photon. This rate provides insight into the intensity of the laser and is essential for understanding the laser's performance and applications in various fields.
Video consigliato:
Percorso guidato
6:34Fluid Speed & Volume Flow Rate
Pratica correlata
Domanda del libro di testo
Potassium and gold cathodes are used in a photoelectric-effect experiment. For each cathode, find: The threshold frequency.
628
views
Domanda del libro di testo
What quantum number of the hydrogen atom comes closest to giving a 100-nm-diameter electron orbit?
50
views
Domanda del libro di testo
Potassium and gold cathodes are used in a photoelectric-effect experiment. For each cathode, find: The stopping potential if the wavelength is 220 nm.
180
views
Domanda del libro di testo
Find the radius of the electron’s orbit, the electron’s speed, and the energy of the atom for the first three stationary states of He+.
103
views
Domanda del libro di testo
BIO The wavelengths of light emitted by a firefly span the visible spectrum but have maximum intensity near 550 nm. A typical flash lasts for 100 ms and has a power output of 1.2 mW. How many photons does a firefly emit in one flash if we assume that all light is emitted at the peak intensity wavelength of 550 nm?
648
views