Skip to main content
Ch 14: Periodic Motion
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Non è quello che usi tu?Cambia libro di testo
Capitolo 14, Problema 24a

For the oscillating object in Fig. E14.4, what is its maximum speed?
Graph depicting position vs. time for a simple harmonic oscillator, illustrating periodic motion.

Guida verificata passo dopo passo
1
Identify the amplitude (A) of the oscillation from the graph. The amplitude is the maximum displacement from the equilibrium position, which is the highest point on the graph.
Determine the angular frequency (ω) of the oscillation. This can be found using the formula ω = 2π/T, where T is the period of the oscillation. The period is the time it takes for one complete cycle, which can be measured from the graph.
Use the formula for maximum speed in simple harmonic motion, which is v_max = Aω. This formula relates the maximum speed to the amplitude and angular frequency.
Substitute the values of amplitude (A) and angular frequency (ω) into the formula to find the maximum speed.
Ensure the units are consistent when substituting into the formula. If the amplitude is in centimeters, convert it to meters if necessary to match the standard SI units for speed (meters per second).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
5m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Simple Harmonic Motion (SHM)

Simple Harmonic Motion is a type of periodic motion where an object oscillates around an equilibrium position. The motion is characterized by a restoring force proportional to the displacement from the equilibrium, leading to sinusoidal position, velocity, and acceleration graphs. In the context of the given question, the oscillating object follows a predictable pattern, allowing for the calculation of maximum speed.
Video consigliato:
Percorso guidato
07:52
Simple Harmonic Motion of Pendulums

Maximum Speed in SHM

The maximum speed of an object in Simple Harmonic Motion occurs as it passes through the equilibrium position. This speed can be calculated using the formula v_max = ωA, where ω is the angular frequency and A is the amplitude of the motion. Understanding this relationship is crucial for determining the maximum speed from the position vs. time graph provided.
Video consigliato:
Percorso guidato
07:59
Speed Distribution & Special Speeds of Ideal Gases

Amplitude and Angular Frequency

Amplitude is the maximum displacement from the equilibrium position in oscillatory motion, while angular frequency (ω) relates to how quickly the object oscillates, measured in radians per second. The amplitude can be identified from the graph as the maximum height reached, and the angular frequency can be derived from the period of the oscillation, which is the time taken for one complete cycle.
Video consigliato:
Percorso guidato
05:08
Circumference, Period, and Frequency in UCM
Pratica correlata
Domanda del libro di testo

A 0.400-kg object undergoing SHM has ax = -1.80 m/s2 when x = 0.300 m. What is the time for one oscillation?

1781
views
1
rank
Domanda del libro di testo

A 0.500kg0.500\(\operatorname{kg}\) mass on a spring has velocity as a function of time given by vx(t)=−(3.60cm/s)sin[(4.7 rad/s)t−(π/2)]v_{x}(t)=-(3.60\(\operatorname{cm}\)/s)\(\sin\)[(4.7\(\text{ }\)rad/s)t-(\(\pi\)/2)]. What are the period and the force constant of the spring?

1593
views
Domanda del libro di testo

A small block is attached to an ideal spring and is moving in SHM on a horizontal frictionless surface. The amplitude of the motion is 0.165 m. The maximum speed of the block is 3.90 m/s. What is the maximum magnitude of the acceleration of the block?

4788
views
Domanda del libro di testo

A 0.500kg0.500\(\operatorname{kg}\) mass on a spring has velocity as a function of time given by vx(t)=−(3.60cm/s)sin[(4.7 rad/s)t−(π/2)]v_{x}(t)=-(3.60\(\operatorname{cm}\)/s)\(\sin\)[(4.7\(\text{ }\)rad/s)t-(\(\pi\)/2)]. What are the amplitude and the maximum acceleration of the mass?

2484
views
Domanda del libro di testo

A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. The amplitude of the motion is 0.250 m and the period is 3.20 s. What are the speed and acceleration of the block when x = 0.160 m?

2004
views
Domanda del libro di testo

For the oscillating object in Fig. E14.4, what is its maximum acceleration?

2836
views