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Ch. 6 - Inverse Circular Functions and Trigonometric Equations
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 57

Solve each equation for x.
arccos x + arctan 1 = 11π/12

Guida verificata passo dopo passo
1
Recognize that the equation is given as \(\arccos x + \arctan 1 = \frac{11\pi}{12}\), and our goal is to solve for \(x\).
Recall the value of \(\arctan 1\). Since \(\tan \frac{\pi}{4} = 1\), it follows that \(\arctan 1 = \frac{\pi}{4}\).
Substitute \(\arctan 1 = \frac{\pi}{4}\) into the equation to get \(\arccos x + \frac{\pi}{4} = \frac{11\pi}{12}\).
Isolate \(\arccos x\) by subtracting \(\frac{\pi}{4}\) from both sides: \(\arccos x = \frac{11\pi}{12} - \frac{\pi}{4}\).
Simplify the right side by finding a common denominator and then use the definition of arccosine to write \(x = \cos\left(\arccos x\right) = \cos\left(\frac{11\pi}{12} - \frac{\pi}{4}\right)\).

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Inverse trigonometric functions, such as arccos and arctan, return the angle whose trigonometric ratio equals a given value. For example, arccos x gives the angle whose cosine is x, and arctan y gives the angle whose tangent is y. Understanding their ranges and outputs is essential for solving equations involving these functions.
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Solving equations involving inverse trig functions often requires isolating the inverse function, using known angle values, and applying algebraic manipulation. Understanding how to rewrite the equation and use identities or known values is key to finding the solution for x.
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