Beginning & Intermediate Algebra
2x3y2\(\displaystyle\) \(\frac{2x}{3y^2}\)
2x23y2\(\displaystyle\) \(\frac{2x^2}{3y^2}\)
2x3y\(\displaystyle\) \(\frac{2x}{3y}\)
69y2\(\displaystyle\) \(\frac{6}{9y^2}\)