Beginning & Intermediate Algebra
81y316x2\(\displaystyle\) \(\frac{81y^3}{16x^2}\)
27y38x2\(\displaystyle\) \(\frac{27y^3}{8x^2}\)
9y4x\(\displaystyle\) \(\frac{9y}{4x}\)
81y216x\(\displaystyle\) \(\frac{81y^2}{16x}\)