-arch-is-4-units-high-at-x-3-determine-a-and-write-the-full-equation-of-the-arch

Question

A garden arch is shaped like a vertical parabola. The vertex of the arch is 66 units high at x=1x = 1, and the arch is 44 units high at x=3x = 3. Determine the value of aa and write the equation of the arch in the form y=a(x−1)2+6y = a(x - $$1)^2 + 6.$$

Accepted Answer

y=−12(x−1)2+6\displaystyle y = -\frac{1}{2}(x - $$1)^2 + 6$$

Answer

y=12(x−1)2+6\displaystyle y = \frac{1}{2}(x - $$1)^2 + 6$$

Answer

y=−2(x−1)2+6y = -2(x - $$1)^2 + 6$$

Answer

x=2(x−1)2+6{\displaystyle x=$$2(x-1)^2+6$$}

A garden arch is shaped like a vertical parabola. The vertex of the arch is 66 units high at x=1x = 1, and the arch is 44 units high at x=3x = 3. Determine the value of aa and write the equation of the arch in the form y=a(x−1)2+6y = a(x - 1)^2 + 6.

A garden arch is shaped like a vertical parabola. The vertex of the arch is $6$ units high at $x equals 1$ , and the arch is $4$ units high at $x equals 3$ . Determine the value of $a$ and write the equation of the arch in the form $y = a (x - 1)^{2} + 6$ .