2-6y-10-into-vertex-form-x-ay-k2-h-then-identify-the-vertex-and-axis-of-symmetry

Question

Complete the square to convert x=y2+6y+10x = $$y^2 + 6y + 10 $$into vertex form x=a(y−k)2+hx = a(y - $$k)^2 + h. $$Then, identify the vertex and the axis of symmetry.

Accepted Answer

x=(y+3)2+1x = (y + $$3)^2 + 1 $$Vertex: (1,−3)(1, -3) Axis of symmetry: y=−3y = -3

Answer

x=(y+3)2+1x = (y + $$3)^2 + 1 $$Vertex: (1,−3)(1, -3) Axis of symmetry: y=3y = 3

Answer

y=(x+3)2+1y = (x + $$3)^2 + 1 $$Vertex: (−3,1)(-3, 1) Axis of symmetry: x=−3x = -3

Answer

x=(y+3)2−1x = (y + $$3)^2 - 1 $$Vertex: (1,−3)(1, -3) Axis of symmetry: y=3y = 3

Complete the square to convert x=y2+6y+10x = y^2 + 6y + 10 into vertex form x=a(y−k)2+hx = a(y - k)^2 + h. Then, identify the vertex and the axis of symmetry.

Complete the square to convert $x = y^{2} + 6 y + 10$ into vertex form $x = a (y - k)^{2} + h$ . Then, identify the vertex and the axis of symmetry.