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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
10장, 문제 10.2.19

13–52. Limits of sequences
Find the limit of the following sequences or determine that the sequence diverges.


{1 + cos(1⁄n)}

검증된 단계별 안내
1
Identify the given sequence: \(a_n = 1 + \cos\left(\frac{1}{n}\right)\), where \(n\) is a positive integer and \(n \to \infty\).
Recall that as \(n\) approaches infinity, the term \(\frac{1}{n}\) approaches 0, so we need to analyze the behavior of \(\cos\left(\frac{1}{n}\right)\) as its argument approaches 0.
Use the fact that \(\cos(x)\) is continuous and \(\cos(0) = 1\), so \(\lim_{x \to 0} \cos(x) = 1\). Therefore, \(\lim_{n \to \infty} \cos\left(\frac{1}{n}\right) = 1\).
Apply the limit to the entire sequence: \(\lim_{n \to \infty} a_n = \lim_{n \to \infty} \left(1 + \cos\left(\frac{1}{n}\right)\right) = 1 + \lim_{n \to \infty} \cos\left(\frac{1}{n}\right)\).
Combine the results to conclude that the limit of the sequence is \(1 + 1 = 2\).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
1m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Limit of a Sequence

The limit of a sequence is the value that the terms of the sequence approach as the index goes to infinity. If the terms get arbitrarily close to a specific number, the sequence converges to that limit; otherwise, it diverges.
추천 영상:
8:22
Introduction to Sequences

Behavior of the Cosine Function Near Zero

The cosine function is continuous and approaches 1 as its argument approaches 0. Understanding that cos(1/n) approaches cos(0) = 1 as n → ∞ is key to evaluating the limit of sequences involving cosine of reciprocal terms.
추천 영상:
가이드 코스
5:53
Graph of Sine and Cosine Function

Substitution and Limit Laws

Limit laws allow the evaluation of limits by substituting the limit of the inner function into the outer function when the outer function is continuous. Here, since cosine is continuous, we can find the limit by substituting the limit of 1/n into cos(1/n).
추천 영상:
05:21
Finding Limits by Direct Substitution