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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
10장, 문제 10.4.31

23–38. Divergence, Integral, and p-series Tests Use the Divergence Test, the Integral Test, or the p-series test to determine whether the following series converge.
∑ (k = 3 to ∞) 1 / (k − 2)⁴

검증된 단계별 안내
1
Identify the given series: \( \sum_{k=3}^{\infty} \frac{1}{(k-2)^4} \). Notice that the term inside the summation can be rewritten as \( \frac{1}{n^4} \) by letting \( n = k - 2 \). This shifts the index to start from \( n=1 \).
Recognize that the series is a p-series of the form \( \sum_{n=1}^{\infty} \frac{1}{n^p} \) where \( p = 4 \). The p-series test states that such a series converges if and only if \( p > 1 \).
Since \( p = 4 > 1 \), the p-series test indicates that the series converges.
Optionally, you could apply the Integral Test by considering the function \( f(x) = \frac{1}{x^4} \) for \( x \geq 1 \), which is positive, continuous, and decreasing. Then evaluate the improper integral \( \int_1^{\infty} \frac{1}{x^4} \, dx \) to confirm convergence.
Conclude that by the p-series test (and optionally the Integral Test), the series \( \sum_{k=3}^{\infty} \frac{1}{(k-2)^4} \) converges.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Divergence Test

The Divergence Test states that if the limit of the terms of a series does not approach zero, the series diverges. It is a quick initial check to determine if a series cannot converge, but if the limit is zero, the test is inconclusive.
추천 영상:
가이드 코스
05:44
Divergence Test (nth Term Test)

Integral Test

The Integral Test relates a series to an improper integral by comparing the sum of terms to the integral of a corresponding function. If the integral converges, so does the series; if the integral diverges, the series diverges as well. It requires the function to be positive, continuous, and decreasing.
추천 영상:

p-series Test

A p-series is a series of the form ∑ 1/n^p. It converges if and only if p > 1 and diverges otherwise. This test is useful for quickly determining convergence of series with terms involving powers of n.
추천 영상:
가이드 코스
04:30
P-Series and Harmonic Series