Skip to main content
Ch. 2 - Limits
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
2장, 문제 2.82.2

b. Estimate a solution to the equation in the given interval using a root finder.


x^5+7x+5=0; (−1,0)

검증된 단계별 안내
1
First, understand the problem: We need to find a root of the equation x^5 + 7x + 5 = 0 within the interval (-1, 0). A root finder method, such as the bisection method, can be used to estimate the solution.
Start by evaluating the function at the endpoints of the interval. Calculate f(-1) and f(0) to determine if there is a sign change, which indicates a root exists between these points.
Apply the bisection method: Divide the interval into two halves and evaluate the function at the midpoint. If the function changes sign between the midpoint and one of the endpoints, the root lies in that subinterval.
Continue the bisection process: Repeatedly halve the interval and check for sign changes at the midpoints. This iterative process narrows down the interval where the root is located.
Stop the process when the interval is sufficiently small, or when the function value at the midpoint is close enough to zero, indicating an approximate root of the equation.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
3m
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Root Finding

Root finding is a numerical method used to determine the values of x for which a given function f(x) equals zero. Common techniques include the bisection method, Newton's method, and the secant method. These methods iteratively approximate the root by evaluating the function at specific points and refining the interval or estimate until a satisfactory level of accuracy is achieved.
추천 영상:
05:21
Finding Limits by Direct Substitution

Intermediate Value Theorem

The Intermediate Value Theorem states that if a continuous function takes on two values at two points, it must also take on any value between those two points. This theorem is crucial for establishing the existence of roots within a given interval. In the context of the equation x^5 + 7x + 5 = 0, verifying that the function changes sign over the interval (-1, 0) indicates that a root exists within that range.
추천 영상:
가이드 코스
06:11
Fundamental Theorem of Calculus Part 1

Function Behavior and Graphing

Understanding the behavior of the function, including its continuity, increasing or decreasing nature, and critical points, is essential for effective root finding. Graphing the function can provide visual insights into where the function crosses the x-axis, indicating potential roots. Analyzing the function's derivative can also help identify intervals where the function is increasing or decreasing, aiding in the selection of appropriate root-finding methods.
추천 영상:
가이드 코스
5:53
Graph of Sine and Cosine Function
관련 실천
교과서 질문

Use the precise definition of a limit to prove the following limits. Specify a relationship between ε and δ that guarantees the limit exists.

lim x→1 x^4=1

406
views
교과서 질문

If a function f represents a system that varies in time, the existence of lim limtf(t){\(\displaystyle\[\lim\)_{t\(\rightarrow\]\infty\)}{f(t)}} means that the system reaches a steady state (or equilibrium). For the following systems, determine whether a steady state exists and give the steady-state value.


The population of a bacteria culture is given by p(t)=2500t+1p\(\left\)(t\(\right\))=\(\frac{2500}{t+1}\).

400
views
교과서 질문

A sequence is an infinite, ordered list of numbers that is often defined by a function. For example, the sequence {2,4,6,8,…} is specified by the function f(n) = 2n, where n=1,2,3,….The limit of such a sequence is lim n→∞ f(n), provided the limit exists. All the limit laws for limits at infinity may be applied to limits of sequences. Find the limit of the following sequences or state that the limit does not exist. 


{2,3/4,4/9,5/16,…}, which is defined by f(n) = (n+1) / n^2, for n=1,2,3,…

308
views
교과서 질문

Use a graph of f to estimate limxaf(x){\(\displaystyle\]\lim\)_{x\(\to\) a}}f\(\left\)(x\(\right\)) or to show that the limit does not exist. Evaluate f(x) near x=ax=a to support your conjecture.

f(x)=1cos(2x2)(x1)2;a=1f\(\left\)(x\(\right\))=\(\frac{1-\cos\left(2x-2\right)}{\left(x-1\right)^2}\);a=1

328
views
교과서 질문

Determine the points on the interval (0, 5) at which the following functions f have discontinuities. At each point of discontinuity, state the conditions in the continuity checklist that are violated. <IMAGE>

246
views
교과서 질문

Suppose limxa f(x)=L{\(\displaystyle\]\lim\)_{x\(\to\) a}}\(\text{ }\)f\(\left\)(x\(\right\))=L and limxa g(x)=M{\(\displaystyle\]\lim\)_{x\(\to\) a}}\(\text{ }\)g\(\left\)(x\(\right\))=M. Prove that limxa (f(x)g(x))=LM{\(\displaystyle\[\lim\)_{x\(\to\) a}}\(\text{ }\]\left\)(f\(\left\)(x\(\right\))-g\(\left\)(x\(\right\))\(\right\))=L-M.

345
views