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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 5.3.97a

Working with area functions Consider the function ƒ and the points a, b, and c.
(a) Find the area function A (𝓍) = ∫ₐˣ ƒ(t) dt using the Fundamental Theorem.
ƒ(𝓍) = cos 𝓍 ; a = 0 , b = π/2 , c = π

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Step 1: Recall the Fundamental Theorem of Calculus, which states that if A(𝓍) = ∫ₐˣ ƒ(t) dt, then A'(𝓍) = ƒ(𝓍). This means the derivative of the area function A(𝓍) is equal to the original function ƒ(𝓍).
Step 2: To find the area function A(𝓍), integrate ƒ(t) = cos(t) with respect to t from the lower limit a = 0 to the upper limit 𝓍. The integral of cos(t) is sin(t).
Step 3: Apply the definite integral formula: A(𝓍) = ∫ₐˣ ƒ(t) dt = [sin(t)]ₐˣ. Substitute the limits of integration into the antiderivative.
Step 4: Substitute the lower limit a = 0 and the upper limit 𝓍 into the expression: A(𝓍) = sin(𝓍) - sin(0). Simplify the result using the fact that sin(0) = 0.
Step 5: The area function A(𝓍) is now expressed as A(𝓍) = sin(𝓍). This function represents the accumulated area under ƒ(t) = cos(t) from t = 0 to t = 𝓍.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
1m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus connects differentiation and integration, stating that if a function is continuous on an interval, then the integral of its derivative over that interval gives the net change of the function. Specifically, it allows us to evaluate definite integrals using antiderivatives, which is essential for finding area functions.
추천 영상:
가이드 코스
06:11
Fundamental Theorem of Calculus Part 1

Definite Integral

A definite integral represents the signed area under a curve defined by a function over a specific interval [a, b]. It is calculated as the limit of Riemann sums and provides a numerical value that corresponds to the total accumulation of the function's values between the bounds, which is crucial for determining the area function A(x) in the given problem.
추천 영상:
가이드 코스
05:43
Definition of the Definite Integral

Area Function

An area function A(x) is defined as the integral of a function f(t) from a constant lower limit a to a variable upper limit x. This function represents the accumulated area under the curve of f(t) from a to x, and it is essential for understanding how the area changes as x varies, particularly in the context of the problem involving the cosine function.
추천 영상:
05:06
Finding Area When Bounds Are Not Given
관련 실천
교과서 질문

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. Assume ƒ, ƒ', and ƒ'' are continuous functions for all real numbers.                                                                                                                                                           

                                                                                                                                                                    

(a) ∫ ƒ(𝓍) ƒ'(𝓍) d𝓍 = ½ (ƒ(𝓍))² + C.

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교과서 질문

Matching functions with area functions Match the functions ƒ, whose graphs are given in a― d, with the area functions A (𝓍) = ∫₀ˣ ƒ(t) dt, whose graphs are given in A–D.



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교과서 질문

Average value with a parameter Consider the function ƒ(𝓍) = a𝓍 (1―𝓍) on the interval [0, 1], where a is a positive real number.

(a) Find the average value of ƒ as a function of a .

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교과서 질문

{Use of Tech} Midpoint Riemann sums with a calculator Consider the following definite integrals.

(a) Write the midpoint Riemann sum in sigma notation for an arbitrary value of n.


∫₁⁴ 2√𝓍 d𝓍

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교과서 질문

Sigma notation Evaluate the following expressions.

(a)    10                                                                                                                                                                               

       ∑ κ                                                                                                                                                                          

       κ=1                         

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교과서 질문

Approximating displacement The velocity in ft/s of an object moving along a line is given by v = 3t² + 1 on the interval 0 ≤ t ≤ 4, where t is measured in seconds.

(a) Divide the interval [0,4] into n = 4 subintervals, [0,1] , [1.2] , [2,3] , and [3,4]. On each subinterval, assume the object moves at a constant velocity equal to v evaluated at the midpoint of the subinterval, and use these approximations to estimate the displacement of the object on [0, 4] (see part (a) of the figure)

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