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Ch.12 - Parametric and Polar Curves
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
12장, 문제 12.2.79

Circles in general Show that the polar equation
r² - 2r r₀ cos(θ - θ₀) = R² - r₀²
describes a circle of radius R whose center has polar coordinates (r₀, θ₀)

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1
Recall the relationship between polar and Cartesian coordinates: \(x = r \cos\theta\) and \(y = r \sin\theta\). Similarly, the center of the circle has Cartesian coordinates \(x_0 = r_0 \cos\theta_0\) and \(y_0 = r_0 \sin\theta_0\).
Rewrite the given polar equation \(r^2 - 2 r r_0 \cos(\theta - \theta_0) = R^2 - r_0^2\) by expressing \(\cos(\theta - \theta_0)\) using the cosine difference identity: \(\cos(\theta - \theta_0) = \cos\theta \cos\theta_0 + \sin\theta \sin\theta_0\).
Substitute the expressions for \(\cos\theta\) and \(\sin\theta\) in terms of \(x\) and \(y\), and similarly for \(\cos\theta_0\) and \(\sin\theta_0\), to rewrite the equation entirely in terms of \(x\), \(y\), \(x_0\), and \(y_0\).
Simplify the equation to get it into the standard form of a circle: \((x - x_0)^2 + (y - y_0)^2 = R^2\). This will involve expanding and rearranging terms to isolate the squared terms of \((x - x_0)\) and \((y - y_0)\).
Conclude that since the equation matches the standard form of a circle with center \((x_0, y_0)\) and radius \(R\), the original polar equation indeed describes a circle with center at polar coordinates \((r_0, \theta_0)\) and radius \(R\).

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주요 개념

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Polar Coordinates and Conversion to Cartesian Coordinates

Polar coordinates represent points using a radius and an angle (r, θ). To analyze curves like circles, it is often helpful to convert polar equations into Cartesian form using x = r cos θ and y = r sin θ. This conversion allows the use of familiar geometric interpretations and algebraic manipulations.
추천 영상:
05:32
Intro to Polar Coordinates

Equation of a Circle in Cartesian Coordinates

A circle with center (h, k) and radius R in Cartesian coordinates satisfies (x - h)² + (y - k)² = R². Recognizing this form after converting from polar coordinates confirms the geometric nature of the curve. Identifying the center and radius from the equation is key to understanding the shape described.
추천 영상:
05:32
Intro to Polar Coordinates

Use of the Law of Cosines in Polar Form

The given polar equation resembles the law of cosines, which relates the lengths of sides in a triangle to the cosine of an included angle. Interpreting r, r₀, and R as sides and θ - θ₀ as the angle helps to understand the geometric meaning of the equation and its relation to a circle centered at (r₀, θ₀).
추천 영상:
3:37
Convert Equations from Rectangular to Polar
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