Skip to main content
Ch. 3 - Derivatives
3์žฅ, ๋ฌธ์ œ 3.5

Find the derivatives of the functions in Exercises 1โ€“42.


๐”‚ = (x + 1)ยฒ (xยฒ + 2x)

๊ฒ€์ฆ๋œ ๋‹จ๊ณ„๋ณ„ ์•ˆ๋‚ด
1
Identify the function as a product of two functions: \( u(x) = (x + 1)^2 \) and \( v(x) = (x^2 + 2x) \).
Apply the product rule for differentiation, which states that if \( y = u(x) \cdot v(x) \), then \( y' = u'(x) \cdot v(x) + u(x) \cdot v'(x) \).
Differentiate \( u(x) = (x + 1)^2 \) using the chain rule: \( u'(x) = 2(x + 1) \cdot 1 = 2(x + 1) \).
Differentiate \( v(x) = x^2 + 2x \) using the power rule: \( v'(x) = 2x + 2 \).
Substitute \( u(x) \), \( u'(x) \), \( v(x) \), and \( v'(x) \) into the product rule formula to find \( y' \).

๋น„์Šทํ•œ ๋ฌธ์ œ์— ๋Œ€ํ•œ ๊ฒ€์ฆ๋œ ์˜์ƒ ๋‹ต๋ณ€:

์ด ์˜์ƒ ํ•ด๋ฒ•์€ ์œ„ ๋ฌธ์ œ์— ๋„์›€์ด ๋œ๋‹ค๊ณ  ํŠœํ„ฐ๋“ค์ด ์ถ”์ฒœํ•œ ๊ฒƒ์ž…๋‹ˆ๋‹ค.
์˜์ƒ ๊ธธ์ด:
4m
๋„์›€์ด ๋˜์—ˆ๋‚˜์š”?

์ฃผ์š” ๊ฐœ๋…

์งˆ๋ฌธ์— ์˜ฌ๋ฐ”๋ฅด๊ฒŒ ๋‹ตํ•˜๊ธฐ ์œ„ํ•ด ๋ฐ˜๋“œ์‹œ ์ดํ•ดํ•ด์•ผ ํ•˜๋Š” ํ•ต์‹ฌ ๊ฐœ๋…๋“ค์€ ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

Derivative

The derivative of a function measures how the function's output value changes as its input value changes. It is defined as the limit of the average rate of change of the function over an interval as the interval approaches zero. Derivatives are fundamental in calculus for understanding rates of change and are denoted as f'(x) or dy/dx.
์ถ”์ฒœ ์˜์ƒ:

Product Rule

The product rule is a formula used to find the derivative of the product of two functions. If u(x) and v(x) are two differentiable functions, the derivative of their product is given by u'v + uv'. This rule is essential when differentiating functions that are multiplied together, as seen in the given function.
์ถ”์ฒœ ์˜์ƒ:
05:18
The Product Rule

Chain Rule

The chain rule is a method for differentiating composite functions. If a function y is defined as a composition of two functions, such as y = f(g(x)), the chain rule states that the derivative is dy/dx = f'(g(x)) * g'(x). This rule is crucial when dealing with functions that are nested within each other, which may occur in more complex expressions.
์ถ”์ฒœ ์˜์ƒ:
05:02
Intro to the Chain Rule
๊ด€๋ จ ์‹ค์ฒœ
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Derivative Calculations


In Exercises 1โ€“8, given y = f(u) and u = g(x), find dy/dx = f'(g(x)) g'(x).


y = cos u, u = โˆ’x/3

263
views
๊ต๊ณผ์„œ ์งˆ๋ฌธ

In Exercises 41โ€“44, determine whether the piecewise-defined function is differentiable at x = 0.


f(x) = { 2x โˆ’ 1, x โ‰ฅ 0

xยฒ + 2x + 7, x < 0

198
views
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Find the derivatives of the functions in Exercises 1โ€“42.


๐”‚ = xโปยน/ยฒ sec (2x)ยฒ

239
views
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Second Derivatives


Find y'' in Exercises 59โ€“64.


y = x(2x + 1)โด

202
views
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Power Rule for negative integers Use the Derivative Quotient Rule to prove the Power Rule for negative integers, that is,

d/dx (xโปแต) = โˆ’mxโปแตโปยน

where m is a positive integer.

277
views
๊ต๊ณผ์„œ ์งˆ๋ฌธ

The best quantity to order One of the formulas for inventory management says that the average weekly cost of ordering, paying for, and holding merchandise is

A(q) = (km / q) + cm + (hq / 2),

where q is the quantity you order when things run low (shoes, TVs, brooms, or whatever the item might be); k is the cost of placing an order (the same, no matter how often you order); c is the cost of one item (a constant); m is the number of items sold each week (a constant); and h is the weekly holding cost per item (a constant that takes into account things such as space, utilities, insurance, and security).

Find dA/dq and dยฒA/dqยฒ.

155
views