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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
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7장, 문제 7.8.3c

3. Which of the following functions grow faster than x² as x→∞? Which grow at the same rate as x²? Which grow slower?
c. √(x^4 + x^3)

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1
Rewrite the function to better understand its growth rate. The function is \(\sqrt{x^4 + x^3}\). Since the square root is the same as raising to the power \(\frac{1}{2}\), rewrite it as \(\left(x^4 + x^3\right)^{\frac{1}{2}}\).
Factor out the highest power of \(x\) inside the parentheses to simplify the expression. The highest power inside is \(x^4\), so factor it out: \(\left(x^4\left(1 + \frac{1}{x}\right)\right)^{\frac{1}{2}}\).
Use the property of exponents to separate the factors: \(\left(x^4\right)^{\frac{1}{2}} \cdot \left(1 + \frac{1}{x}\right)^{\frac{1}{2}} = x^{4 \cdot \frac{1}{2}} \cdot \left(1 + \frac{1}{x}\right)^{\frac{1}{2}} = x^2 \cdot \left(1 + \frac{1}{x}\right)^{\frac{1}{2}}\).
Analyze the behavior of \(\left(1 + \frac{1}{x}\right)^{\frac{1}{2}}\) as \(x \to \infty\). Since \(\frac{1}{x} \to 0\), this term approaches \(1\).
Conclude that the function behaves like \(x^2\) times a term approaching \(1\), so its growth rate is asymptotically similar to \(x^2\). Therefore, it grows at the same rate as \(x^2\) as \(x \to \infty\).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Asymptotic Growth Rates

Asymptotic growth rates describe how functions behave as the input variable approaches infinity. Comparing growth rates helps determine which functions increase faster, slower, or at the same rate by analyzing dominant terms and their exponents.
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Intro To Related Rates

Dominant Term in Polynomials

In polynomials, the term with the highest power of x dominates the function's behavior for large x. For example, in x^4 + x^3, the x^4 term grows faster and dictates the overall growth rate as x approaches infinity.
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Simplifying Expressions with Radicals

Simplifying expressions involving square roots, such as √(x^4 + x^3), often involves factoring out the highest power inside the root to identify dominant behavior. This helps compare the function's growth rate to simpler functions like x².
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Simplifying Trig Expressions